Question

我有两个元素数量相等的python列表。我只需要减去忽略字符串元素的两个列表的int和float元素。

export class Example {

    stores: Store[] = [];

    constructor() {
        this.stores = [
            new Store("mike", "US"),
            new Store("nelson", "UK")
        ];
    }

    clearData() {
        this.stores = [];
    }

}

现在第三个列表应该是两个列表元素的最终差异

list_1 = [1, 2, 3.0, 'test', 6.5]
list_2 = [2, 3, 10.0, 'test', 12.5]

我可以将字符串值保留在任一列表的list_3中。

Answer 1

这是一种使用列表理解的方法。

演示：

list_1 = [1, 2, 3.0, 'test', 6.5]
list_2 = [2, 3, 10.0, 'test', 12.5]

res = [v if (isinstance(i, str) or isinstance(v, str)) else (i-v) for i,v in zip(list_2, list_1)]
print(res)

输出：

[1, 1, 7.0, 'test', 6.0]

Answer 2

当两个值都是数字时，此列表推导将返回差值；如果不是这种情况，则将从<%@ taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c" %> <!DOCTYPE html> <html lang="en"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <meta charset="utf-8"> <meta http-equiv="X-UA-Compatible" content="IE=edge"> <meta name="viewport" content="width=device-width, initial-scale=1"> <title>OPTIMA Dashboard</title>  <link href="vendors/bootstrap/dist/css/bootstrap.min.css" rel="stylesheet">  <link href="vendors/font-awesome/css/font-awesome.min.css" rel="stylesheet">  <link href="vendors/nprogress/nprogress.css" rel="stylesheet">  <link href="vendors/animate.css/animate.min.css" rel="stylesheet">  <link href="build/css/custom.min.css" rel="stylesheet">  <script src='https://www.google.com/recaptcha/api.js'></script> </head> <body class="login"> <div> <a class="hiddenanchor" id="signup"></a> <a class="hiddenanchor" id="signin"></a> <div class="login_wrapper"> <div class="animate form login_form"> <section class="login_content"> <form method="POST" action="/admin/submitLogin" commandName="index" modelAttribute="login"> <h1>Login Form</h1> <div> <span style="border: none; box-shadow: none; font-size: 12; color: red;">${status}</span> <input type="text" class="form-control" placeholder="Username" name="username" required="" /> </div> <div> <input type="password" class="form-control" placeholder="Password" name="password" required="" /> </div> <div class="g-recaptcha" data-sitekey="${key}"></div> <br /> <div> <button type="reset" class="btn btn-default submit">Reset</button> <button type="submit" class="btn btn-default submit">Log In</button> </div> <div class="clearfix"></div> <div class="separator"> <div class="clearfix"></div> <br /> <div> <h1> <i class="fa fa-paw"></i> OPTIMA </h1> <p> <i class="fa fa-copyright"></i> 2017 Jatelindo Perkasa Abadi </p> </div> </div> </form> </section> </div> </div> </div> </body> </html>返回值：

list_1

from numbers import Number

list_1 = [1, 2, 3.0, 'test', 6.5]
list_2 = [2, 3, 10.0, 'test', 12.5]

list_3 = [y-x if isinstance(x,Number) and isinstance(y,Number) 
              else x for x,y in zip(list_1,list_2)]

Answer 3

您也可以尝试以下方法。

>>> list_1 = [1, 2, 3.0, 'test', 6.5]
>>> list_2 = [2, 3, 10.0, 'test', 12.5]
>>>
>>> list_3 = [item2-item1 if type(item1) is int or type(item1) is float else item1 if item1 else item2 for item1, item2 in zip(list_1, list_2)]
>>>
>>> list_3
[1, 1, 7.0, 'test', 6.0]
>>>

减去不同数据类型的两个python列表的元素

3 个答案: