如何获得每日未结交易的每日计数？

Question

我有一个名为 shoe_service

的表

被取消表示错误的交易或错误，不予计算。将null的closed_at表示尚未关闭。 我已经能够使用以下命令找到特定日期有多少笔交易：

这将返回我想要的确切数据：

但是我不想只在特定的日子里需要手动输入和更改。 我想要一张表格，该表格针对每一天和鞋子的类型返回一行。

即

我希望有1460（= 4 * 365）行数据。 本质上，我想打开我的查询以将其扩展到每一天，而不仅仅是我输入的单个时间戳。数据通过时间戳记录。

我想我必须进行某种顺序的日期联接，但是我不确定该怎么做？

很抱歉无法嵌入图片

Answer 1

请尝试以下查询。

select cast(opened_at as date) as date,shoe_type,count(*) as [open] from shoeTable where state='open' group by cast(opened_at as date),shoe_type order by cast(opened_at as date)

Answer 2

尝试以下一个：：（一年中的第一个日期到当前日期），但是如果需要365天，则将查询中的getdate（）替换为一年中的最后一个日期。

 WITH mycte AS
    (
      SELECT cast(DATEADD(yy, year(GETDATE()) - 1900, 0)  as datetime) DateValue
      UNION ALL
      SELECT  DateValue + 1
      FROM    mycte   
      WHERE   DateValue + 1 < getdate()
    )
    SELECT  cast(DateValue as date) as [Date],'boot' as Shoe_type,isnull([open],0) as [Open]
    FROM    mycte a left join (select cast(dt as date) as date,shoe_type,count(*) as [open] from YOURTABLENAME where state='open' and shoe_type='boot' group by cast(dt as date),shoe_type ) b
    on cast(DateValue as date)=b.date 
    union 
    SELECT  cast(DateValue as date) as [Date],'sandal' as Shoe_type,isnull([open],0) as [Open]
    FROM    mycte a left join (select cast(dt as date) as date,shoe_type,count(*) as [open] from YOURTABLENAME where state='open' and shoe_type='sandal' group by cast(dt as date),shoe_type ) b
    on cast(DateValue as date)=b.date 
    union
    SELECT  cast(DateValue as date) as [Date],'trainer' as Shoe_type,isnull([open],0) as [Open]
    FROM    mycte a left join (select cast(dt as date) as date,shoe_type,count(*) as [open] from YOURTABLENAME where state='open' and shoe_type='trainer' group by cast(dt as date),shoe_type ) b
    on cast(DateValue as date)=b.date
    union
    SELECT  cast(DateValue as date) as [Date],'shoe' as Shoe_type,isnull([open],0) as [Open]
    FROM    mycte a left join (select cast(dt as date) as date,shoe_type,count(*) as [open] from YOURTABLENAME where state='open' and shoe_type='shoe' group by cast(dt as date),shoe_type ) b
    on cast(DateValue as date)=b.date 
    OPTION (MAXRECURSION 0)