对于Django项目,创建基于函数的任务非常干净。只需在Django应用中创建task.py并开始编写此示例的任务即可,该示例取自http://docs.celeryproject.org/en/latest/django/first-steps-with-django.html
上的官方celery文档。from __future__ import absolute_import, unicode_literals
from celery import shared_task
@shared_task
def add(x, y):
return x + y
@shared_task
def mul(x, y):
return x * y
但是有时基于功能的任务紧密相关,并且不太可重用。所以我想创建基于类的芹菜任务,该任务已在官方网站上进行了记录。遵循https://github.com/celery/celery/issues/3874之后,我可以创建示例任务,但是我不确定创建基于类的任务的正确方法。
from __future__ import absolute_import, unicode_literals
from celery import shared_task, Task
import time
from celery import current_app
@shared_task
def add(x, y):
time.sleep(5)
return x + y
@shared_task
def mul(x, y):
return x * y
# Sample class based task for testing
class AnotherTask(current_app.Task):
name = 'tasks.another_task'
def __init__(self, x, y):
self.x = x
self.y = y
def run(self):
time.sleep(5)
return self.x + self.y
# We need to manually register this class based task
current_app.tasks.register(AnotherTask(3, 4))
我可以调用此任务,但每个调用结果值都相同
(workflow) alok@alok-MacBookAir:~/exp/expdjango/mysite$ ./manage.py shell
Python 3.6.3 (default, Oct 3 2017, 21:45:48)
Type "copyright", "credits" or "license" for more information.
IPython 5.1.0 -- An enhanced Interactive Python.
? -> Introduction and overview of IPython's features.
%quickref -> Quick reference.
help -> Python's own help system.
object? -> Details about 'object', use 'object??' for extra details.
In [1]: from polls.tasks import *
In [2]: r = AnotherTask(3,4).delay()
In [3]: r.get()
Out[3]: 7
In [4]: r = AnotherTask(5,6).delay()
In [5]: r.get()
Out[5]: 7
创建和调用基于类的任务是否正确?
答案 0 :(得分:1)
基于类的任务实际上在每个运行时仅实例化一次。如果要对任务进行参数化,请向run
方法中添加参数:
class AnotherTask(current_app.Task):
name = 'tasks.another_task'
def run(self, x, y):
time.sleep(5)
return x + y
然后您可以这样称呼它:
r = AnotherTask().delay(3, 4)
# Or
r = AnotherTask().apply_async(args=[3, 4])
这在the docs on class based tasks中也有描述,尤其是在instantiation section中。