Question

我正在尝试按array的值Dictionaries从最新到最早对timeStamp进行排序

错误：二进制运算符'<'无法应用于两个'Any？'操作数

timeStamp的值作为Int保存到Dictionary中：

timeStamp = inviteDict["timeStamp"] as? Int

字典：

[
"type": "invite",
"complimentId": key,
"status": status,
"timeStamp": timeStamp!,
 "fromUser": user
]

功能-合并两个arrays元组，在通过array传递之前，我需要按timeStamp对handler进行排序：

    func getInvitesAndCompliments(forUserId forId: String, handler: @escaping ([[String : Any]], Bool) -> ()){

            var invitesAndCompliments = [[String : Any]]()

            var invites = [[String : Any]]()

            var compliments = [[String : Any]]()

            getComplimentsReceived(forUserId: forId) { (complimentsDict, success) in
                invitesAndCompliments.removeAll()
                compliments = complimentsDict
                invitesAndCompliments = invites + compliments
                handler(invitesAndCompliments, true)
            }

            getInvitesReceived(forUserId: forId) { (invitesDict, success) in
                invitesAndCompliments.removeAll()
                invites = invitesDict
                invitesAndCompliments = compliments + invites

                //sort array by timeStamp value
                let sorted_invitesAndCompliments = invitesAndCompliments.sorted(by: { $0["timeStamp"] < $1["timeStamp"] })

                handler(sorted_invitesAndCompliments, true)
            }


        }//end func

Answer 1

如下更新代码：

let sorted_invitesAndCompliments = invitesAndCompliments.sorted { ($0["timeStamp"] as! Int) < ($1["timeStamp"]  as! Int)}

我希望这对您有用。

Answer 2

从字典中获取值的结果始终是Any?，您必须精简类型

let sorted_invitesAndCompliments = invitesAndCompliments.sorted(by: { ($0["timeStamp"] as! Int) < $1["timeStamp"] as! Int })

为避免这种情况，请使用自定义结构。

Answer 3

我建议不要使用强制转换，如果值为空，则可能会崩溃。检查以下代码：

let sorted_invitesAndCompliments = invitesAndCompliments.sorted(by: {
    guard let timestamp1 = $0["timeStamp"] as? Int else {return false}
    guard let timestamp2 = $1["timeStamp"] as? Int else {return false}
    return timestamp1 < timestamp2
})

如瓦迪安建议在这种情况下使用自定义结构。

快速排序字典数组并获取运算符不能应用于任何

3 个答案: