在这种情况下,我想将用户ID转移到State中定义的数组。
当我单击复选框以将其选中时,我想这样做,而当我取消选中该复选框时,我想从阵列中删除用户ID
import React, { Component } from "react";
import {
View,
Text,
StyleSheet,
FlatList,
AsyncStorage
} from "react-native";
import axios from 'axios';
import { Button, Container, Content, Header, Body, Left, Right, Title } from 'native-base';
import Icon from 'react-native-vector-icons/Ionicons';
import { List, ListItem, SearchBar, CheckBox } from "react-native-elements";
// const itemId = this.props.navigation.getParam('itemId', 'NO-ID');
// const otherParam = this.props.navigation.getParam('otherParam', 'some default value');
class TeacherSubjectSingle extends Component{
static navigationOptions = {
header : null
}
// static navigationOptions = {
// headerStyle: {
// backgroundColor: '#8E44AD',
// },
// headerTintColor: '#fff',
// }
state = {
class_id: null,
userid: null,
usertype: null,
student_list: [],
faq : [],
checked: [],
}
componentWillMount = async () => {
const {class_id, student_list, userid, usertype} = this.props.navigation.state.params;
await this.setState({
class_id : class_id,
student_list : student_list,
userid : userid,
usertype : usertype,
})
console.log(this.state.class_id)
var result = student_list.filter(function( obj ) {
return obj.class_section_name == class_id;
});
this.setState({
student_list: result[0]
})
}
renderSeparator = () => {
return (
<View
style={{
height: 1,
width: "100%",
backgroundColor: "#CED0CE",
}}
/>
);
};
checkItem = (item) => {
const { checked } = this.state;
console.log(item)
if (!checked.includes(item)) {
this.setState({ checked: [...checked, item] });
} else {
this.setState({ checked: checked.filter(a => a !== item) });
}
console.log(checked)
};
render(){
return (
<Container>
<Header style={{ backgroundColor: "#8E44AD" }}>
<Left>
<Button transparent onPress={()=> this.props.navigation.navigate('ClassTeacher')}>
<Icon name="ios-arrow-dropleft" size={24} color='white' />
</Button>
</Left>
<Body>
<Title style={{ color: "white" }}>{this.state.class_id}</Title>
</Body>
<Right>
{this.state.checked.length !== 0 ? <Button transparent onPress={()=> this.props.navigation.navigate('ClassTeacher')}>
<Text>Start Chat</Text>
</Button> : null}
</Right>
</Header>
<View style={{flex: 1, backgroundColor: '#fff'}}>
<List containerStyle={{ borderTopWidth: 0, borderBottomWidth: 0 }}>
<FlatList
data={this.state.student_list.students}
extraData={this.state.checked}
renderItem={({ item }) => (
<ListItem
// roundAvatar
title={<CheckBox
title={item.name}
checkedColor='#8E44AD'
onPress={() => this.checkItem(item.userid)}
checked={this.state.checked.includes(item.userid)}
/>}
// subtitle={item.email}
// avatar={{ uri: item.picture.thumbnail }}
//containerStyle={{ borderBottomWidth: 0 }}
onPress={()=>this.props.navigation.navigate('IndividualChat', {
rc_id: item.userid,
userid: this.state.userid,
usertype: this.state.usertype,
subject_name: this.state.student_list.subject_name
})}
/>
)}
keyExtractor={item => item.userid}
ItemSeparatorComponent={this.renderSeparator}
/>
</List>
</View>
</Container>
);
}
}
export default TeacherSubjectSingle;
const styles = StyleSheet.create({
container:{
flex:1,
alignItems:'center',
justifyContent:'center'
}
});
这是相同的代码,我为相同的对象创建了一个函数checkItem()
并且可以正常工作,唯一的问题是,当我单击第一个项目时,它将输出空白数组,选择第二项,它将返回包含第一项的数组,依此类推。请帮助我解决它,谢谢
答案 0 :(得分:2)
尝试以下代码:
checkItem = (e) => {
let alreadyOn = this.state.checked; //If already there in state
if (e.target.checked) {
alreadyOn.push(e.target.name); //push the checked value
} else {
//will remove if already checked
_.remove(alreadyOn, obj => {
return obj == e.target.name;
});
}
console.log(alreadyOn)
this.setState({checked: alreadyOn});
}
答案 1 :(得分:1)
这是因为您是在setState之后立即打印this.state.checked
值,而setState是异步的,因此不会立即更新状态值。
您可以使用setState回调方法来检查更新的状态值。
这样写:
checkItem = (item) => {
const { checked } = this.state;
let newArr = [];
if (!checked.includes(item)) {
newArr = [...checked, item];
} else {
newArr = checked.filter(a => a !== item);
}
this.setState({ checked: newArr }, () => console.log('updated state', newArr))
};
检查此答案以获取有关setState的更多详细信息:
Why calling setState method doesn't mutate the state immediately?
答案 2 :(得分:0)
类似,带有事件侦听器和数组的.push
方法。
var checkboxes = document.querySelectorAll('input[type=checkbox]');
var myArray = [];
for (var i = 0; i < checkboxes.length; i++) {
checkboxes[i].addEventListener("click", function(e) {
myArray.push(e.target.value);
console.log(myArray);
});
};
<div>
<input type="checkbox" name="feature" value="scales" />
<label >Scales</label>
</div>
<div>
<input type="checkbox" name="feature" value="horns" />
<label >Horns</label>
</div>
<div>
<input type="checkbox" name="feature" value="claws" />
<label >Claws</label>
</div>