Question

我正在构建我的应用程序，并显示构建成功，但是当我尝试在我的设备中运行时，它表明您的应用程序再次停止打开，如果有人帮助我解决此问题，则仅在登录活动中会发生这种情况，请帮助我

我的登录活动代码

package com.eassycars.www.licencespot;

import android.content.Intent;
import android.os.Build;
import android.os.Handler;
import android.support.annotation.NonNull;
import android.support.annotation.RequiresApi;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.text.TextUtils;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.ProgressBar;
import android.widget.RelativeLayout;
import android.widget.Toast;

import com.google.android.gms.tasks.OnCompleteListener;
import com.google.android.gms.tasks.Task;
import com.google.firebase.auth.AuthResult;
import com.google.firebase.auth.FirebaseAuth;


public class Activity_Login extends AppCompatActivity {


    private EditText inputEmail, inputPassword;
    private FirebaseAuth mAuth;
    private ProgressBar progressBar;
    private Button singups,forgotpass,logins;


    RelativeLayout really1, really2;

    Handler handler = new Handler();
    Runnable runnable = new Runnable() {

        @Override
        public void run() {
            really1.setVisibility(View.VISIBLE);
            really2.setVisibility(View.VISIBLE);
        }
    };

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        //Get Firebase auth instance
        mAuth = FirebaseAuth.getInstance();

        if (mAuth.getCurrentUser() != null) {
            startActivity(new Intent(Activity_Login.this, MainActivity.class));
            finish();
        }

        // set the view now
        setContentView(R.layout.activity__login);


        inputEmail = (EditText) findViewById(R.id.email);
        inputPassword = (EditText) findViewById(R.id.password);
        progressBar = (ProgressBar) findViewById(R.id.progressBar);
        singups = (Button) findViewById(R.id.singups);
        logins = (Button) findViewById(R.id.logins);
        forgotpass = (Button) findViewById(R.id.forgotpass);

        //Get Firebase auth instance
        mAuth = FirebaseAuth.getInstance();

        singups.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                startActivity(new Intent(Activity_Login.this, singup.class));
            }
        });

        forgotpass.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                startActivity(new Intent(Activity_Login.this, ForgotPassword.class));
            }
        });
        really1 = (RelativeLayout) findViewById(R.id.rellayl);
        really2 = (RelativeLayout) findViewById(R.id.really2);
        handler.postDelayed(runnable, 2000);

        logins.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                String email = inputEmail.getText().toString();
                final String password = inputPassword.getText().toString();

                if (TextUtils.isEmpty(email)) {
                    Toast.makeText(getApplicationContext(), "Enter email address!", Toast.LENGTH_SHORT).show();
                    return;
                }

                if (TextUtils.isEmpty(password)) {
                    Toast.makeText(getApplicationContext(), "Enter password!", Toast.LENGTH_SHORT).show();
                    return;
                }

                progressBar.setVisibility(View.VISIBLE);

                //authenticate user
                mAuth.signInWithEmailAndPassword(email, password)
                        .addOnCompleteListener(Activity_Login.this, new OnCompleteListener<AuthResult>() {
                            @Override
                            public void onComplete(@NonNull Task<AuthResult> task) {
                                // If sign in fails, display a message to the user. If sign in succeeds
                                // the auth state listener will be notified and logic to handle the
                                // signed in user can be handled in the listener.
                                progressBar.setVisibility(View.GONE);
                                if (!task.isSuccessful()) {
                                    // there was an error
                                    if (password.length() < 6) {
                                        inputPassword.setError(getString(R.string.minimum_password));
                                    } else {
                                        Toast.makeText(Activity_Login.this, getString(R.string.auth_failed), Toast.LENGTH_LONG).show();
                                    }
                                } else {
                                    Intent intent = new Intent(Activity_Login.this, MainActivity.class);
                                    startActivity(intent);
                                    finish();

                                }
                            }
                        });
            }
        });
    }
}

这些是我的登录活动代码，无法找到错误，并且android studio还显示您没有任何错误，但是有一个错误是当我使用登录屏幕时我的应用程序不断停止。

我使用Firebase构建登录活动

Answer 1

请从logcat发布您的错误消息。

如果从线程调用Handler导致NullPointerException，

尝试在handler中致电您的onCreate

public class LoginActivity extends Activity {

@Override
public void onCreate(Bundle bundle){
    super.onCreate(bundle);
    //move this HERE!!  
    new Handler().post(new Runnable() {
    @Override
      public void run() {
       // Code here will run in UI thread
      }
    });
  }
}

应用程序保持停止再次打开，并在LoginActivity.java上发生错误

1 个答案: