我有一个DRF ViewSet,我要向其中添加CanViewAndEditStaff
权限。我只希望某些用户(user.access_level < 2
)能够查看工作人员列表。在我的Permissions类中,如何区分对list
视图和get
项目视图的调用。这是我的权限类别:
class CanViewAndEditStaff(permissions.BasePermission):
def has_permission(self, request, view):
# IF THIS IS A LIST VIEW, CHECK ACCESS LEVEL
if ( request.user.access_level < 3 ):
return True
# ELSE, CONTINUE ON TO OBJECT PERMISSIONS
def has_object_permission(self,request,view,account):
# admin can do anything
if ( request.user.access_level == 1 ):
return True
# view/edit/delete
else:
# users can view their own account
if account == request.user:
return True
elif account.access_level >= request.user.access_level:
return True
return False
答案 0 :(得分:4)
class CanViewAndEditStaff(permissions.BasePermission):
def has_permission(self, request, view):
# IF THIS IS A LIST VIEW, CHECK ACCESS LEVEL
if (view.action == 'list' and request.user.access_level < 3 ):
return True
# ELSE, CONTINUE ON TO OBJECT PERMISSIONS
您可以使用view.action来了解这是列表还是其他内容。
答案 1 :(得分:0)
这不能完全准确地解决问题,但是该技术适用。
我在Ykh的答案上使用了一个变体,该变体允许在显示各种不同模型的许多视图中广泛使用同一权限类。
在视图类中,我添加了一个属性以区分原始视图,从而允许进行适当的对象比较以确定权限
# views.py
class SomeView(ListAPIView):
permission_classes = (IsPermd, )
is_some_view = True
class SomeOtherView(RetrieveAPIView
permission_classes = (IsPermd, )
is_some_other_view = True
# permissions.py
class IsPermd(BasePermission):
def has_object_permissions(self, request, view, obj):
if hasattr(view, 'is_some_view'):
# whatever special considerations
if hasattr(view, 'is_some_other_view'):
# whatever other special considerations
这感觉有些笨拙,但是直到我找到更好的方法为止,我都会坚持下去。