Question

这是mysql中的JSON

[
  {
        "debt_type": "Personal loan",
        "amount_borrowed": "2100",
        "repayment_amount": "179",
        "remaining_balance": "1900",
        "repayment_frequency": "Fortnightly",
        "financial_institution": "Money3"
    },
    {
        "debt_type": "Commercial loan",
        "amount_borrowed": "2700",
        "repayment_amount": "199",
        "remaining_balance": "1200",
        "repayment_frequency": "Fortnightly",
        "financial_institution": "Money3"
    }
]

什么SQL查询来查找应用程序ID，其中bond_type =“ Commericial_loan” AND amount_borrowed> 2300 AND剩余余额<30000

这是表结构

Id  | application_id  | debts (JSON data mentioned above)

我写的查询是这个

SELECT application_id FROM `table_name` 
where json_contains(debts, '{"debt_type" : "Commercial loan" , "amount_borrowed": "2700"}')

但是此查询对amount_borrowed取2700的精确值，如何添加大于或小于条件

编辑开始

这是我尝试过的另一个查询，但结果为空，应该会查询此查询以找到应用程序ID，其中amount_borrowed在100-20000和loan_type =商业贷款之间，但结果为空

SELECT id, application_id FROM `table_name` 
where 
debts REGEXP '{"loan_type":"Commercial loan", "amount_borrowed":"(1[0-9][0-9][0-9]|2000)"}'

编辑结束

SQL JSON查询可应用大于或小于条件

0 个答案: