我的sql语句类似这里的问题Room Booking Query。
如果一间公寓只有一个预订,则以下查询有效。但是如果一间公寓有多个预订,那么即使在请求的时间段内无法使用,也会出现此公寓。
SELECT DISTINCT `apartment`.*
FROM `apartment` `apartment`
LEFT JOIN `booking` `booking` ON `apartment`.`uid` = `booking`.`apartment`
WHERE (
NOT(
( `booking`.`start` <= '2018-07-23')
AND
( `booking`.`end` >= '2018-07-21')
)
)
有人可以帮我写正确的sql吗?
更新: 根据马特·雷恩斯(Matt Raines)的提示,我在预订表上添加了带有公寓uid的野外公寓。我非常感谢您的任何建议,这些建议可以帮助我编写正确的SQL语句!
此处已更新演示数据:
--
-- Table structure for table `apartment`
--
CREATE TABLE `apartment` (
`uid` int(11) NOT NULL,
`title` varchar(255) COLLATE utf8_unicode_ci NOT NULL DEFAULT '',
`bookings` int(10) UNSIGNED NOT NULL DEFAULT '0'
)
--
-- Data for table `tx_apartments_domain_model_apartment`
--
INSERT INTO `apartment` (`uid`, `title`, `bookings`) VALUES
(1, 'Apartment 1', 2),
(2, 'Apartment 2', 1),
(3, 'Apartment 3', 1),
(4, 'Apartment 4', 1);
--
-- Table structure for table `booking`
--
CREATE TABLE `booking` (
`uid` int(11) NOT NULL,
`start` date DEFAULT '0000-00-00',
`end` date DEFAULT '0000-00-00',
`apartment` int(10) UNSIGNED NOT NULL DEFAULT '0'
)
--
-- Data for table `booking`
--
INSERT INTO `booking` (`uid`, `start`, `end`, `apartment`) VALUES
(1, '2018-07-18', '2018-07-20', 1),
(2, '2018-07-21', '2018-07-23', 1),
(3, '2018-07-18', '2018-07-20', 2);
答案 0 :(得分:1)
请考虑以下内容。
DROP TABLE IF EXISTS apartment;
CREATE TABLE apartment
(apartment_id SERIAL PRIMARY KEY
,apartment_name varchar(255) NOT NULL
);
INSERT INTO apartment VALUES
(1, 'Apartment 1'),
(2, 'Apartment 2'),
(3, 'Apartment 3'),
(4, 'Apartment 4');
DROP TABLE IF EXISTS booking;
CREATE TABLE booking
(booking_id SERIAL PRIMARY KEY
,start_date DATE NOT NULL
,end_date DATE NOT NULL
,apartment_id INT NOT NULL
);
INSERT INTO booking VALUES
(1, '2018-07-18', '2018-07-20', 1),
(2, '2018-07-21', '2018-07-23', 1),
(3, '2018-07-18', '2018-07-20', 2);
SELECT a.*
FROM apartment a
LEFT
JOIN booking b
ON b.apartment_id = a.apartment_id
AND b.start_date <= '2018-07-23'
AND b.end_date > '2018-07-21'
WHERE b.booking_id IS NULL;
+--------------+----------------+
| apartment_id | apartment_name |
+--------------+----------------+
| 2 | Apartment 2 |
| 3 | Apartment 3 |
| 4 | Apartment 4 |
+--------------+----------------+
实际上,除非绑定在交易中,否则SELECT这样的选择是毫无意义的,因为在您仍在检查可用性时,另一个用户可以轻松地进行预订。