Question

我正在尝试创建一个脚本，该脚本接受多个用户输入。当我调用脚本并提供多个输入时，如果提供多个输入，则脚本将不会执行。我在这里做错什么了。

#! /bin/bash

server_list=()

echo "Enter server name:  "
readarray -t  servername

declare -p servername

sudo showsudolocal $servername | tr -d '$' | sed -e '/^$/d' | tee output.txt
sed -i 1,8d output.txt

mapfile -t myArray < output.txt
count=${#myArray[@]}


for (( i=1; i<$count; ))
#for i in `seq 1 $count`
do
        str="${myArray[$i]}"
        echo "str is $str"

        IFS=',' read -r -a array <<< "$str"
        i=$((i+2))
        username="${array[0]}"
        groupname="${array[1]}"


        echo "Username is $username"
        if [[ -z "${array[0]}" ]] || [[ "${array[0]}" == *'*'* ]]
        then
                echo "group"
                sudo docentcmd $servername centclicmd adquery group $groupname
                cat /etc/group | grep $groupname
        else
                echo "User"
                sudo docentcmd $servername centclicmd adquery user $username
                cat /etc/passwd | grep $username
        fi

done

接受多个用户输入

0 个答案: