带有API调用的Node.Js函数返回未定义

Question

我是JS的新手，我使用Google的新闻API创建了此函数，以返回格式为“ S”的查询“ q”上的前n条文章的字符串。

当我console.log变量“ articles”时，它成功返回一个字符串，但是当我调用该函数（例如bitcoinNews = queryToSlack（'Bitcoin'，3））时，它返回的是未定义的。

似乎是示波器问题？有什么想法吗？

function queryToSlack(q, n) {
    //logic to get weekAgo and today
    newsapi.v2.everything({
        q: q,
        from: weekAgo,
        to: today,
        language: 'en',
        sortBy: 'popularity',
        page: 1
    }).then(response => {
        if (response.articles[0].title) {
            console.log(response.totalResults + " articles found");
            var articles = '<' + response.articles[0].url + '|*' + response.articles[0].title + '*>\n*' +
                response.articles[0].source.name + '*\n' + response.articles[0].description + '\n';
            var i = 1;
            while (i < n) {
                articles = articles + '<' + response.articles[i].url + '|*' + response.articles[i].title + '*>\n*' +
                    response.articles[i].source.name + '*\n' + response.articles[i].description + '\n';
                i++;
            }

            //this successfully returns n articles
            console.log(articles);

            //returns undefined
            return articles;

        } else {
            console.log('No articles found');
            var noArticles = 'No articles on ' + q + ' found this week';
            return noArticles;
        }
    });
}