使用if语句时出错

时间:2018-07-16 12:27:50

标签: r if-statement statistics

我正在尝试根据另一个矩阵z定义新的矩阵x。这就是我所做的:

x = structure(
  .Data = c(5012, 3257,2638,-898,1734,2642,1828,599,-54,172,
            -106,4179,-1111,5270,3116,1817,-103,0,535,NA,
            3410,5582,4881,2268,2594,3479,0,603,NA, NA,
            5655,5900,4211,5500,2159,2658,984, NA, NA, NA,
            1092,8473,6271,6333,3786,-225, NA, NA, NA, NA,
            1513,4932,5257,1233,2917, NA , NA, NA, NA, NA,
            -557,3463,6926,1368, NA, NA, NA, NA, NA, NA,
            1351,5596,6165, NA, NA, NA, NA, NA, NA, NA,
            3133,2262, NA, NA, NA , NA , NA , NA, NA , NA,
            2063, NA, NA, NA , NA , NA , NA, NA , NA, NA),
  .Dim = c(10,10))

x = t(x)
r=ncol(x)
z = matrix(ncol = r, nrow = r)
for(i in 1:r){
  for(j in 1:r){
    if(x[i,j]>0){
      z[i,j] = 1
    }
    else if(x[i,j]<0){
      z[i,j] = -1
    }
    else {
      z[i,j]=0
    }
  }
}

但是我遇到了错误:

Error in if (x[i, j] > 0) { : missing value where TRUE/FALSE needed

我该如何解决?

1 个答案:

答案 0 :(得分:2)

if命中NA

时发生了问题
for(i in 1:r){
   for(j in 1:r){
if(!is.na(x[i,j]) & x[i,j]>0){
  z[i,j] = 1
}
else if(!is.na(x[i,j]) & x[i,j]<0){
  z[i,j] = -1
}
else {
  z[i,j]=0
  }
 }
}