销售点系统-过时的-如果声明未按预期工作

Question

几个月前，我用C ++制作了一个示例销售点系统。现在，我已经了解了更多有关C ++的知识，我试图对它进行更好的复制。但是，我没有从程序的“签出”部分中使用的ifStatement中获得行为。我想要的是让程序在用户输入“ y”时退出，并让其返回到其他任何输入的主菜单。但是，它只是退出任何输入。我对C ++还是很陌生，不明白为什么。任何帮助，将不胜感激。我已将代码包含在此帖子中。

#include <iostream>

包括

包括

使用命名空间标准；

int main（int nNumberofArgs，char * pszArgs []） {

int nBookQuantity = 0;
int nBatQuantity = 0;
int nHatQuantity = 0;

cout << endl
<< "Hello, and welcome to Books, Bats 'n Hats2.0"
<< endl << endl
<< "1. books"
<< endl << endl
<< "2. bats"
<< endl << endl
<< "3. hats"
<< endl << endl
<< "4. void item(s)"
<< endl << endl
<< "5. checkout"
<< endl << endl
<< "6. exit"
<< endl << endl;





while(true){

int nVoidNumber;



int nValue;
cout << "Please make a selection: ";
cin >> nValue;


        switch(nValue)
        {
            case 1:
                cout << "Please enter a quantity of books to purchase: ";
                cin >> nBookQuantity;
                continue;


            case 2:
                cout << "Please enter a quantity of bats to purchase: ";
                cin >> nBatQuantity;
                continue;

            case 3:
                cout << "Please enter a quantity of hats to purchase: ";
                cin >> nHatQuantity;
                continue;

            case 4:
                cout << endl << endl
                << "(1) book(s)"
                << "(2) bat(s)"
                << "(3) hat(s)"
                << "(4) cancel"
                << "Please select an item number to void items: ";
                cin >> nVoidNumber;

                switch(nVoidNumber)
                {
                    case 1:
                        nBookQuantity = 0;
                        cout << "the books are Voided!";
                        break;

                    case 2:
                        nBatQuantity = 0;
                        cout << "the bats are Voided!";
                        break;

                    case 3:
                        nHatQuantity = 0;
                        cout << "the hats are Voided!";
                        break;

                    case 4:
                        cout << "cancelling...";
                        break;


                }

                continue;

            case 5:
                cout << endl
                << "Welcome to the checkout! -- Books, Bats 'n Hats2.0"
                << endl << endl
                << "book(s): " << nBookQuantity << endl
                << "bat(s): " << nBatQuantity << endl
                << "hat(s): " << nHatQuantity
                << endl;

                cout << "To checkout, enter 'y'. To continue shopping, enter 'n'. Please make a selection: ";

                char cCheckoutChoice;
                cin >> cCheckoutChoice;



                if(cCheckoutChoice = 'y'){


                    cout << "Thankyou for shopping at Books, Bats 'n Hats. Please come again!";
                    break;

                }if(cCheckoutChoice = 'n'){

                    continue;

                }else{

                    cout << "command not understood - continuing...";
                    continue;

                }


            case 6:
                cout << endl
                << "Thank you for visiting Books, Bats 'n Hats2.0"
                << endl;
                break;




        }
break;

}

返回0；

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