我需要您的帮助来解决以下问题
column1 Column2
1 a
1 b
2 c
3 d
4 e
我想与col2的元素联系以获得相同的col1值,并将结果作为变量返回到单列中。
结果:| 1 | a,b |
感谢您的帮助。
答案 0 :(得分:0)
使用concat函数
select concat(case when t.column1 is not null then t.column1 else end,
case when t.column2 is not null then t.column2 else end) as col1 from your_table as t
inner join
(
select column1 from your_table
group by column1
having count(*)>1
) as T1
t.column1=T1.column1
答案 1 :(得分:0)
根据需要填充tbename和column1,column2
SELECT distinct CAT.column1 AS [column1],
STUFF(( SELECT ',' + SUB.column2 AS [text()]
FROM tbename SUB
WHERE
SUB.column1 = CAT.column1
FOR XML PATH('')
), 1, 1, '' )
AS [column2]
FROM tbename CAT
对于oracle,代码11g +
select column1, listagg(column2,',') within group( order by column1 )
from tbename group by gr