Question

我正在接受用户的3个联系人，然后作为注册过程的一部分移至主屏幕。但是，当某些细节未填写时，我需要对其进行检查并举杯或提示您填充所有细节。然后，用户可以返回以填充其余的详细信息-空白。填写完详细信息后，用户单击注册按钮，应用程序将切换到主屏幕。

请帮助查找当前代码的问题。我是一个完整的初学者。任何帮助表示赞赏。

import android.content.Context;
import android.content.Intent;
import android.content.SharedPreferences;

import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Toast;


public class AddContacts extends AppCompatActivity {

  SharedPreferences sharedPreferences;

  SharedPreferences.Editor editor;

  Button registerbtn;
  EditText name1, num1, name2, num2, name3, num3;
  String emname1,emname2,emname3;
  int emnum1,emnum2,emnum3;

  @Override

  protected void onCreate(Bundle savedInstanceState) {

    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_addcontacts);


    sharedPreferences =  this.getSharedPreferences("universe.sk.syndriveapp.addcontacts", Context.MODE_PRIVATE);
    editor = sharedPreferences.edit();

    registerbtn= findViewById(R.id.registerbtn);

    name1 = findViewById(R.id.name1);
    num1 = findViewById(R.id.num1);

    name2 = findViewById(R.id.name2);
    num2 = findViewById(R.id.num2);

    name3 = findViewById(R.id.name3);
    num3 = findViewById(R.id.num3);

    registerbtn.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) {

            emname1 = name1.getText().toString();
            emnum1 = Integer.parseInt(num1.getText().toString());
            emname2 = name2.getText().toString();
            emnum2 = Integer.parseInt(num2.getText().toString());
            emname3 = name3.getText().toString();
            emnum3 = Integer.parseInt(num3.getText().toString());

            if (emname1.isEmpty() || emname2.isEmpty() || emname3.isEmpty()){
                Toast.makeText(AddContacts.this,"Please fill all details!",Toast.LENGTH_SHORT).show();

            }
            else {

                editor.putString("name1", emname1);
                editor.putInt("num1", emnum1);
                editor.putString("name2", emname2);
                editor.putInt("num2", emnum2);
                editor.putString("name3", emname3);
                editor.putInt("num3", emnum3);

                editor.apply();
                Toast.makeText(AddContacts.this,"Registration Success",Toast.LENGTH_SHORT).show();
                startActivity(new Intent(AddContacts.this,NavigationActivity.class));
            }


                        }});


         }

}

Answer 1

显示onClick(view);后删除Toast
onClick(view);仅在用户单击按钮并

时才应触发

用try / catch块包围所有解析器：

try {
    emnum1 = Integer.parseInt(num1.getText().toString());
} catch (NumberFormatException e) {
    e.printStackTrace();
    enum1 = -1
}

如果TextView不包含有效数字，您可以将-1更改为所需的值

输入联系人并将其转到主屏幕

1 个答案: