因此,我能够添加搜索输入,以过滤从此处的帮助数据库中接收到的数据, 任何人都可以引导我了解如何过滤多个输入并显示搜索结果。我想按searchedValue,filterDay,filterCity进行筛选。.现在,该应用程序正在显示数据库中项目的整个列表,或者仅显示searchedValue输入中列出的内容。
如果有人可以向我发送文档,说明如何仅在搜索时从db获取数据,而不是每次刷新时都不断获取该数据。 如果我的问题在这里不清楚,我感到抱歉。
谢谢。
import React, { Component } from 'react';
import { Table, Input } from 'reactstrap';
import { connect } from 'react-redux';
import { getItems, deleteItem } from "../actions/itemActions";
import PropTypes from 'prop-types';
class Directory extends Component {
constructor() {
super();
this.state = {
searchedValue: '',
filterDay: '',
filterCity: ''
};
}
componentDidMount() {
this.props.getItems();
}
onDeleteClick = (id) => {
this.props.deleteItem(id);
}
onSearch = e => {
this.setState({ searchedValue: e.target.value });
}
onFilterDay = e => {
this.setState({ filterDay: e.target.value });
}
onFilterCity = e => {
this.setState({ filterCity: e.target.value });
}
render() {
const { items } = this.props.item;
const filteredNames = items.filter((item) => item.MeetingName.includes(this.state.searchedValue));
return(
<div>
<Input type="text" placeholder="search" onChange={this.onSearch} value={this.state.searchedValue} />
<Input type="select" name="day" onChange={this.onFilterDay} value={this.state.filterDay}>
<option>SUNDAY</option><option>MONDAY</option><option>TUESDAY</option>
</Input>
<Input type="select" name="day" onChange={this.onFilterCity} value={this.state.filterCity}>
<option>DANA POINT</option><option>LAGUNA BEACH</option><option>SAN CLEMENTE</option>
</Input>
<br/>
<Table>
<thead>
<tr>
<th>Day</th><th>Time</th><th>Meeting Name</th><th>Address</th><th>City</th><th>Zip Code</th><th></th>
</tr>
</thead>
<tbody>
{filteredNames.map(({ _id, Day, Time, MeetingName, Address, City, Zip }) => (
<tr key={_id}>
<td>{Day}</td><td>{Time}</td><td>{MeetingName}</td><td>{Address}</td><td>{City}</td><td>{Zip}</td>
{/*<Button
className="remove-btn"
color="danger"
size="sm"
onClick={this.onDeleteClick.bind(this, _id)}
>
×
</Button>*/}
</tr>
))}
</tbody>
</Table>
</div>
);
}
}
Directory.propTypes = {
getItems: PropTypes.func.isRequired,
item: PropTypes.object.isRequired
}
const mapStateToProps = (state) => ({
item: state.item
})
export default connect(
mapStateToProps,
{ getItems, deleteItem }
)(Directory);
答案 0 :(得分:2)
我最近在项目中进行了多次搜索,您可以将其作为示例
searchBy = () => {
let searchBy = [];
{
searchBy.push(
...this.state.originalResponse.filter(item => {
let searchText =
this.state.searchText != ""
? item.question
.toLowerCase()
.search(this.state.searchText.toLowerCase()) !== -1
: true;
let category =
this.state.category != ""
? item.type.toLowerCase() === this.state.category.toLowerCase()
: true;
let level =
this.state.level != ""
? item.difficulty.toLowerCase() === this.state.level.toLowerCase()
: true;
return searchText && category && level;
})
);
}
console.table(searchBy, ["id", "question", "difficulty", "type"]);
this.setState({ userArray: searchBy });
};
该组件从后端获取数据并基于多重搜索显示数据。希望获得帮助