Question

我刚刚开始将php文件包含到我的代码中，因此不必复制和粘贴大量内容。我曾经将数据库连接放在同一个文件中，但是自从将它放在另一个文件中以来，它就不会运行sql语句。

有效的原始内容

    $username = "user";
    $password = "pass";
    $database = "db";
    $hostname = "localhost";

    $conn = new mysqli($hostname,$username,$password,$database) or die(mysqli_error());
    $salt = 'salt';
    $test = rand();
    $pw_hash = md5($salt.$test);
    $isContractor = 0;
    if($_POST['userType'] == "Contractor") $isContractor = 1;

    $sql = "INSERT INTO `UserHash` (`HashID`, `UserID`, `IsContractor`) VALUES ('".$pw_hash."', null, ".$isContractor.")";
    $query = mysqli_query($conn, $sql);
    if(!$query){
        die("Error Found " . mysqli_error($conn));
    }else{
        echo '<div class="alert alert-success" role="alert">User Hash Created: ' . $pw_hash . '</div>';
    }

单独的文件：

/Company/API/DatabaseConnection.php
    $username = "user";
    $password = "pass";
    $database = "db";
    $hostname = "localhost";

    $conn = new mysqli($hostname,$username,$password,$database) or die(mysqli_error());

Hash.php
    include "../Company/API/DatabaseConnection.php";
    $salt = 'B7u3C0w';
    $test = rand();
    $pw_hash = md5($salt.$test);
    $isContractor = 0;
    if($_POST['userType'] == "Contractor") $isContractor = 1;

    $sql = "INSERT INTO `UserHash` (`HashID`, `UserID`, `IsContractor`) VALUES ('".$pw_hash."', null, ".$isContractor.")";
    $query = mysqli_query($conn, $sql);
    if(!$query){
        die("Error Found " . mysqli_error($conn));
    }else{
        echo '<div class="alert alert-success" role="alert">User Hash Created: ' . $pw_hash . '</div>';
    }

这将返回来自！$ query的“发现错误”，但没有不会打印出错误。

Answer 1

文件未提取正确的目录。

我不使用../ [文件名]，我只需要/ [文件名]

更正后的代码为：

include "/Company/API/DatabaseConnection.php";

包括服务器连接文件错误

1 个答案: