如何检测带有特定字母的单词并将其返回到包含它们的列表中

Question

我想创建一个函数，当给定句子和字母时，该函数返回一个列表，其中包含该字母中句子中的所有单词。我想使用列表推导来返回列表。以下是预期的输出。

    sentence = "Anyone who has never made a mistake has never tried 
    anything new"
    words_containing(sentence, 'a')
['Anyone', 'has', 'made', 'a', 'mistake', 'has', 'anything']

关于如何进行这项工作的任何想法？

Answer 1

def get_words (sentence, letter):
    all_words_list = (sentence.split())
    selected_words_list = [word for word in all_words_list if letter in word]
    return selected_words_list

print (get_words ("Anyone who has never made a mistake has never tried anything new", "a"))

Answer 2

def get_words (sentence, letter):
    capital_letter = letter.capitalize()
    all_words_list = (sentence.split())
    selected_words_list = [word for word in all_words_list if letter in word or capital_letter in word]
    return selected_words_list

print (get_words ("Anyone who has never made a mistake has never tried anything new", "a"))