Question

我是新手，我想以数组格式从此字符串中提取所有IP地址

## take your original `sparsed` data frame, where `User` is numeric
sparsed$User <- as.numeric(
                   factor(as.character(sparsed$User),
                          levels = sort(unique(sparsed$User)))
                   )
## no need to do anything with `Movie` at it's already contiguous numeric from 1
sparse <- sparseMatrix(i = sparsed$Movie,
                       j = sparsed$User,
                       x = sparsed$Rating)

#8 x 15 sparse Matrix of class "dgCMatrix"
#                                  
#[1,] 3 . . . 1 . . . 2 . . . . . .
#[2,] . . . . . 4 . . 5 . . . . 3 .
#[3,] 3 2 . . . . . 4 . . 2 . . 5 .
#[4,] . . . 5 . . . . 3 . . . . . .
#[5,] 3 . 4 5 . . 1 . . . . . 3 2 4
#[6,] . . . . 2 . . . . . . 3 . . .
#[7,] . . . . . . . . 1 2 . . . . .
#[8,] 1 . . . . . . . . . . . . . .

当我跳过一步时，我将获得所有IP，这意味着当我使用$ copy [2]时我将获得第二个IP。我想提取所有ip而不跳过该步骤。

Answer 1

$str = "ghg shjsja 192.168.1.2 hbkjNKKSJKKN HKJCBKJLKKL 12.15.14.45 " & _
       "KJBKJABCKBNDKQ djfsjdkfhnwk kjwenfkjdsnf knfflksnf KHBKJABCKJQDH " & _
       "1.1.1.1 2.2.2.2"

$copy = StringRegExp($str, "((?:\d{1,3}\.){3}\d{1,3})", 3)

For $i = 0 To UBound($copy) -1
    ConsoleWrite($copy[$i] & @CRLF)
    MsgBox(0, "", $copy[$i])
Next

将输出

192.168.1.2
12.15.14.45
1.1.1.1
2.2.2.2

代替

192.168.1.2
1.
12.15.14.45
14.
1.1.1.1
1.
2.2.2.2
2.

内部捕获组开始处的?:使它不会捕获，而只是一个小组。外层群体捕获内部群体以及其他角色在外部捕获组中作为单个[step | capture]。

自动脚本从字符串中提取所有IP地址

1 个答案: