我是一名初级C#程序员,正在尝试开发一个库,允许我封装解析从NWS返回的XML的令人讨厌的细节,并返回表示数据的集合。
我的SOAP请求将以这种形式返回XML文档:
<?xml version="1.0" encoding="UTF-8"?>
<dwml version="1.0" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="http://www.nws.noaa.gov/forecasts/xml/DWMLgen/schema/DWML.xsd">
<head>
<product srsName="WGS 1984" concise-name="time-series" operational-mode="official">
<title>NOAA's National Weather Service Forecast Data</title>
<field>meteorological</field>
<category>forecast</category>
<creation-date refresh-frequency="PT1H">2009-02-04T20:01:00Z</creation-date>
</product>
<source>
<more-information>http://www.nws.noaa.gov/forecasts/xml/</more-information>
<production-center>Meteorological Development Laboratory<sub-center>Product Generation Branch</sub-center></production-center>
<disclaimer>http://www.nws.noaa.gov/disclaimer.html</disclaimer>
<credit>http://www.weather.gov/</credit>
<credit-logo>http://www.weather.gov/images/xml_logo.gif</credit-logo>
<feedback>http://www.weather.gov/feedback.php</feedback>
</source>
</head>
<data>
<location>
<location-key>point1</location-key>
<point latitude="42.23" longitude="-83.27"/>
</location>
<moreWeatherInformation applicable-location="point1">http://forecast.weather.gov/MapClick.php?textField1=42.23&textField2=-83.27</moreWeatherInformation>
<time-layout time-coordinate="local" summarization="none">
<layout-key>k-p24h-n7-1</layout-key>
<start-valid-time>2009-02-04T07:00:00-05:00</start-valid-time>
<end-valid-time>2009-02-04T19:00:00-05:00</end-valid-time>
<start-valid-time>2009-02-05T07:00:00-05:00</start-valid-time>
<end-valid-time>2009-02-05T19:00:00-05:00</end-valid-time>
<start-valid-time>2009-02-06T07:00:00-05:00</start-valid-time>
<end-valid-time>2009-02-06T19:00:00-05:00</end-valid-time>
<start-valid-time>2009-02-07T07:00:00-05:00</start-valid-time>
<end-valid-time>2009-02-07T19:00:00-05:00</end-valid-time>
<start-valid-time>2009-02-08T07:00:00-05:00</start-valid-time>
<end-valid-time>2009-02-08T19:00:00-05:00</end-valid-time>
<start-valid-time>2009-02-09T07:00:00-05:00</start-valid-time>
<end-valid-time>2009-02-09T19:00:00-05:00</end-valid-time>
<start-valid-time>2009-02-10T07:00:00-05:00</start-valid-time>
<end-valid-time>2009-02-10T19:00:00-05:00</end-valid-time>
</time-layout>
<time-layout time-coordinate="local" summarization="none">
<layout-key>k-p24h-n6-2</layout-key>
<start-valid-time>2009-02-04T19:00:00-05:00</start-valid-time>
<end-valid-time>2009-02-05T08:00:00-05:00</end-valid-time>
<start-valid-time>2009-02-05T19:00:00-05:00</start-valid-time>
<end-valid-time>2009-02-06T08:00:00-05:00</end-valid-time>
<start-valid-time>2009-02-06T19:00:00-05:00</start-valid-time>
<end-valid-time>2009-02-07T08:00:00-05:00</end-valid-time>
<start-valid-time>2009-02-07T19:00:00-05:00</start-valid-time>
<end-valid-time>2009-02-08T08:00:00-05:00</end-valid-time>
<start-valid-time>2009-02-08T19:00:00-05:00</start-valid-time>
<end-valid-time>2009-02-09T08:00:00-05:00</end-valid-time>
<start-valid-time>2009-02-09T19:00:00-05:00</start-valid-time>
<end-valid-time>2009-02-10T08:00:00-05:00</end-valid-time>
</time-layout>
<parameters applicable-location="point1">
<temperature type="maximum" units="Fahrenheit" time-layout="k-p24h-n7-1">
<name>Daily Maximum Temperature</name>
<value>15</value>
<value>19</value>
<value>33</value>
<value>46</value>
<value>41</value>
<value>43</value>
<value>44</value>
</temperature>
<temperature type="minimum" units="Fahrenheit" time-layout="k-p24h-n6-2">
<name>Daily Minimum Temperature</name>
<value>-2</value>
<value>16</value>
<value>29</value>
<value>32</value>
<value>27</value>
<value>32</value>
</temperature>
</parameters>
</data>
</dwml>
我正在尝试将此XML中的最大和最小临时值放在单独的字符串集合中,而忽略使用LINQ的“name”元素。
编辑: 这是我用来从Web Reference获取XML的代码:
WeatherNWS.ndfdXML client = new TestNWS.WeatherNWS.ndfdXML();
string XMLZip = client.LatLonListZipCode("48180");
XElement myElement = XElement.Parse(XMLZip);
string[] myString = myElement.Value.Split(',');
decimal lat = Convert.ToDecimal(myString[0]);
decimal lon = Convert.ToDecimal(myString[1]);
weatherParametersType parameters = new weatherParametersType();
parameters.maxt = true;
parameters.mint = true;
string XML = client.NDFDgen(lat, lon, productType.timeseries, DateTime.Now, DateTime.Now.AddDays(7), parameters);
答案 0 :(得分:3)
这应该能够为您获得最高温度,您只需要更改where过滤器以获得最低温度
using System.Xml.Linq;
\\...
XDocument xmlDoc = XDocument.Load("YourXml.xml");
var maximums = from tempvalue in xmlDoc.Descendants("temperature").Elements("value")
where tempvalue.Parent.Attribute("type").Value == "maximum"
select (string)tempvalue;
List<string> returnme = maximums.ToList<string>();
return returnme;
希望得到这个帮助。
注意:我在C#中使用Linq to Xml有点生疏,所以它可能不是最优雅的解决方案。
答案 1 :(得分:0)
您可能需要解析使用xpath返回的xml来提取所需的数据。有一个简短的例子here。
或者你可以创建一个镜像xml结构的类结构,并使用XmlSerializer将xml反序列化为对象,但在这种情况下,这可能比它的价值更麻烦。