Question

我要遍历我拥有的URL对象数组中的所有对象

class Url(object):
    pass

a = Url()
a.url = 'http://www.heroku.com'
a.result = 0
b = Url()
b.url = 'http://www.google.com'
b.result = 0
c = Url()
c.url = 'http://www.wordpress.com'
c.result = 0

urls = [a, b, c]

for i, u in urls:
    print(i)
    print(u)

但是，当我运行此脚本时，它会返回以下错误：

TypeError: cannot unpack non-iterable Url object

该如何解决？

Answer 1

尝试一下：

class Url(object):
    pass

a = Url()
a.url = 'http://www.heroku.com'
a.result = 0
b = Url()
b.url = 'http://www.google.com'
b.result = 0
c = Url()
c.url = 'http://www.wordpress.com'
c.result = 0

urls = [a, b, c]

for i in urls:
    print(i)

遍历URL。要获取结果和网址（我认为您正在尝试这样做），请执行以下操作：

class Url(object):
    pass

a = Url()
a.url = 'http://www.heroku.com'
a.result = 0
b = Url()
b.url = 'http://www.google.com'
b.result = 0
c = Url()
c.url = 'http://www.wordpress.com'
c.result = 0

urls = [a, b, c]

for c,i in enumerate(urls):
    print("index is ",c)
    print(i.result)
    print(i.url)

无法解包不可迭代的对象/通过python中的对象数组进行迭代

1 个答案: