Question

我试图弄清楚如何在Excel工作表中读取数据，并在Excel工作表中（而不是在Python控制台中）将结果打印到右侧一列。下面是我正在测试的代码。它似乎可以正常工作，但是只在控制台中显示结果，我真的想将结果写入Excel中的相邻单元格（列B）。

<Grid Width="128" Height="128" Panel.ZIndex="1">
    <Ellipse Fill="Aqua"></Ellipse>
    <Path Fill="LightBlue" Stroke="Black" Name="TriOne">
        <Path.Data>
            <PathGeometry>
                <PathFigure x:Name="fig" StartPoint="44, 32" IsClosed="True">
                    <LineSegment Point="44, 64"/>
                    <LineSegment x:Name="middle" Point="100, 64"/>
                    <LineSegment Point="100, 64"/>
                </PathFigure>
            </PathGeometry>
        </Path.Data>
        <Path.Triggers>
            <EventTrigger RoutedEvent="Polygon.MouseUp">
                <BeginStoryboard>
                    <Storyboard>
                        <PointAnimation 
                            Storyboard.TargetName="fig"
                            Storyboard.TargetProperty="StartPoint"
                            From="44,32" To="32,32"
                        />
                        <PointAnimation 
                            Storyboard.TargetName="middle"
                            Storyboard.TargetProperty="Point"
                            From="100, 64" To="90, 54"
                        />
                    </Storyboard>
                </BeginStoryboard>
            </EventTrigger>
        </Path.Triggers>
    </Path>
    <Polygon Fill="LightBlue" Stroke="Black" Name="TriTwo" >
        <Polygon.Points>

            <Point X="44" Y="96"></Point>
            <Point X="44" Y="64"></Point>
            <Point X="100" Y="64"></Point>
        </Polygon.Points>
    </Polygon>
</Grid>

Answer 1

使用cell.offset(column=1)获取下一个单元格。

Answer 2

这很容易：

如果已确定要写入B列：

for rowno,row in enumerate(ws.iter_rows('A{}:A{}'.format(ws.min_row,ws.max_row)),start=1):
    for cell in row:
        if isinstance(cell.value, str):
            print('string')
            ws.cell(row=rowno,column=2).value = str("string")
        elif isinstance(cell.value, int):
            print('integer')
            ws.cell(row=rowno,column=2).value = str("integer")
        elif isinstance(cell.value, float):
            print('float')
            ws.cell(row=rowno,column=2).value = str("float")
wb.save('C:\\Users\\Excel\\Desktop\\Book1.xlsx')

更多通用答案：

from openpyxl.utils import get_column_letter
from openpyxl.utils import coordinate_from_string, column_index_from_string

for rowno,row in enumerate(ws.iter_rows('A{}:A{}'.format(ws.min_row,ws.max_row)),start=1):
    for cell in row:
        if isinstance(cell.value, str):
            xy = coordinate_from_string(cell.coordinate)
            colno = column_index_from_string[0]
            ws.cell(row=rowno, column=colno+1).value = str("string")
        elif isinstance(cell.value, int):
            xy = coordinate_from_string(cell.coordinate)
            colno = column_index_from_string[0]
            ws.cell(row=rowno, column=colno+1).value = str("string")
        elif isinstance(cell.value, float):
            xy = coordinate_from_string(cell.coordinate)
            colno = column_index_from_string[0]
            ws.cell(row=rowno, column=colno+1).value = str("string")
wb.save('C:\\Users\\Excel\\Desktop\\Book1.xlsx')

评估Excel单元格值并将结果打印在同一行的右一列

2 个答案: