Question

目前，我已按照以下方式从数据库中检索了此数据，

—network

如何将表格更改为类似的内容？

outlier(sample.data, plot = TRUE, col.main = NA)
title("My Title")

我通过使用peewee从数据库中连接多个表来获取数据下面是我检索和格式化数据的完整代码

+------------+--------------+-------+-----+-------------+-----------+------------------+-----------------+
    | Monitor ID | Casting Date | Label | AGE | Client Name |  Project  | Average Strength | Average Density |
    +------------+--------------+-------+-----+-------------+-----------+------------------+-----------------+
    |    1082    |  2018-07-05  |  b52  |  1  |  Trial Mix  | Trial Mix |      21.78       |      2.436      |
    |    1082    |  2018-07-05  |  b52  |  2  |  Trial Mix  | Trial Mix |      33.11       |      2.406      |
    |    1082    |  2018-07-05  |  b52  |  4  |  Trial Mix  | Trial Mix |      43.11       |      2.447      |
    |    1082    |  2018-07-05  |  b52  |  8  |  Trial Mix  | Trial Mix |      48.22       |      2.444      |
    |    1083    |  2018-07-05  |  B53  |  1  |  Trial Mix  | Trial Mix |      10.44       |      2.421      |
    |    1083    |  2018-07-05  |  B53  |  2  |  Trial Mix  | Trial Mix |       20.0       |      2.400      |
    |    1083    |  2018-07-05  |  B53  |  4  |  Trial Mix  | Trial Mix |      27.78       |      2.397      |
    |    1083    |  2018-07-05  |  B53  |  8  |  Trial Mix  | Trial Mix |      33.33       |      2.409      |
    |    1084    |  2018-07-05  |  B54  |  1  |  Trial Mix  | Trial Mix |      12.89       |      2.430      |
    |    1084    |  2018-07-05  |  B54  |  2  |  Trial Mix  | Trial Mix |      24.44       |      2.427      |
    |    1084    |  2018-07-05  |  B54  |  4  |  Trial Mix  | Trial Mix |      34.22       |      2.412      |
    |    1084    |  2018-07-05  |  B54  |  8  |  Trial Mix  | Trial Mix |      41.56       |      2.501      |
    +------------+--------------+-------+-----+-------------+-----------+------------------+-----------------+

Answer 1

您必须透视数据，因为MariaDB没有透视，您可以在sql中完成它：

SELECT
    MonitorID,
    CastingDate,
    Label,
    ClientName,
    Project,
    SUM(IF(Age=1, AverageStrength, 0)) AS AvgStr1,
    SUM(IF(Age=2, AverageStrength, 0)) AS AvgStr2,
    SUM(IF(Age=4, AverageStrength, 0)) AS AvgStr4,
    SUM(IF(Age=8, AverageStrength, 0)) AS AvgStr8,
    SUM(IF(Age=1, AverageDensity, 0)) AS AvgDensity1,
    SUM(IF(Age=2, AverageDensity, 0)) AS AvgDensity2,
    SUM(IF(Age=4, AverageDensity, 0)) AS AvgDensity4,
    SUM(IF(Age=8, AverageDensity, 0)) AS AvgDensity8
FROM
    YourTable
GROUP BY MonitorID, CastingDate, Label, ClientName, Project, Age
ORDER BY MonitorID, CastingDate;

从数据库列创建行

1 个答案: