我在oracle数据库中工作,并收到以下错误:
用于SQL Server的Microsoft OLE DB提供程序:无效的对象名称
我也尝试加入where子句,但我也收到
以下是查询:
select UE_invoice.InvoiceNo,
UE_invoice.DueDate,
UE_payment.CheckNo,
UE_payment.Amount
from
(select tblTransaction.InvoiceNo,
tblTransaction.DueDate
from tblTransaction,
tblTransactionType
where
tblTransaction.Type = tblTransactionType.TransactionType
and
tblTransaction.Date >= '01/01/2018'
and
tblTransaction.Type = -88) UE_invoice,
(select tblTransaction.InvoiceNo,
tblTransaction.DueDate,
tblTransaction.CheckNo,
tblTransaction.Amount
from tblTransaction,
tblTransactionType
where
tblTransaction.Type = tblTransactionType.TransactionType
and
tblTransaction.Date >= '01/01/2018'
and
tblTransaction.Type = -86) UE_payment
Left outer join UE_invoice on UE_invoice.InvoiceNo = UE_payment.InvoiceNo
答案 0 :(得分:1)
这不是使用“表表达式”的LEFT OUTER JOIN
的语法。试试:
select UE_invoice.InvoiceNo,
UE_invoice.DueDate,
UE_payment.CheckNo,
UE_payment.Amount
from (
select tblTransaction.InvoiceNo,
tblTransaction.DueDate,
tblTransaction.CheckNo,
tblTransaction.Amount
from tblTransaction,
tblTransactionType
where
tblTransaction.Type = tblTransactionType.TransactionType
and
tblTransaction.Date >= '01/01/2018'
and
tblTransaction.Type = -86
) UE_payment
Left outer join (
select tblTransaction.InvoiceNo,
tblTransaction.DueDate
from tblTransaction,
tblTransactionType
where
tblTransaction.Type = tblTransactionType.TransactionType
and
tblTransaction.Date >= '01/01/2018'
and
tblTransaction.Type = -88
) UE_invoice on UE_invoice.InvoiceNo = UE_payment.InvoiceNo
答案 1 :(得分:0)
尝试更换
Left outer join UE_invoice on UE_invoice.InvoiceNo = UE_payment.InvoiceNo
使用
where UE_invoice.InvoiceNo = UE_payment.InvoiceNo