SQL将重复的记录合并到一行

Question

我有一个SQL Server 2016数据库，其中有几千条记录。

当前以类似方式显示记录；

我想得到这个结果；

然后我将数据导出到Excel。

基本上，一个人和多个帐户类型有多个联系方式，而不是每个详细信息都占用一个新行，我需要将它们全部折叠成一行并添加列，我可以创建一个具有必要时插入列。

我尝试了这些解决方案的变体；

By Taryn

By Hassan-我不知道我需要加入什么以及在哪里加入。

By Brad C-在此操作上我取得了一些成功，因为它已将该数据库中的表截断了。

很抱歉，其他一些链接却被掩盖了。

模式

CREATE TABLE [dbo].[Contacts] 
(
    [emplid] [float] NULL,
    [emcoid] [float] NULL,
    [name] [varchar](50) NULL,
    [conttp] [varchar](50) NULL,
    [phone] [varchar](50) NULL,
    [fax] [varchar](50) NULL,
    [email] [varchar](50) NULL,
    [auth] [float] NULL,
    [ainits] [varchar](50) NULL,
    [adate] [datetime] NULL,
    [atime] [datetime] NULL,
    [uinits] [varchar](50) NULL,
    [udate] [datetime] NULL,
    [utime] [datetime] NULL
) ON [PRIMARY]
GO

测试数据

INSERT [dbo].[Contacts_NEW] ([emplid], [emcoid], [name], [conttp], [phone], [fax], [email], [auth], [ainits], [adate], [atime], [uinits], [udate], [utime]) 
VALUES (100, 103, N'MR Bert Ernie', N'PENS', N'1800100300', NULL, N'bert.ernie@mail.com', 1, N'MK785487', CAST(N'2016-08-17T00:00:00.000' AS DateTime), CAST(N'2068-02-07T00:00:00.000' AS DateTime), N'MK785487', CAST(N'2016-08-17T00:00:00.000' AS DateTime), CAST(N'2068-02-07T00:00:00.000' AS DateTime))
INSERT [dbo].[Contacts_NEW] ([emplid], [emcoid], [name], [conttp], [phone], [fax], [email], [auth], [ainits], [adate], [atime], [uinits], [udate], [utime]) 
VALUES (100, 104, N'MR Bert Ernie', N'OFFI', N'1800100300', NULL, N'bert.ernie@mail.com', 1, N'MK785487', CAST(N'2016-08-17T00:00:00.000' AS DateTime), CAST(N'2068-02-07T00:00:00.000' AS DateTime), N'MK785487', CAST(N'2016-08-17T00:00:00.000' AS DateTime), CAST(N'2068-02-07T00:00:00.000' AS DateTime))
INSERT [dbo].[Contacts_NEW] ([emplid], [emcoid], [name], [conttp], [phone], [fax], [email], [auth], [ainits], [adate], [atime], [uinits], [udate], [utime])    
VALUES (100, 105, N'MR Bert Ernie', N'CONT', N'1800100300', NULL, N'bert.ernie@mail.com', 1, N'MK785487', CAST(N'2016-08-17T00:00:00.000' AS DateTime), CAST(N'2068-02-07T00:00:00.000' AS DateTime), N'MK785487', CAST(N'2016-08-17T00:00:00.000' AS DateTime), CAST(N'2068-02-07T00:00:00.000' AS DateTime))
INSERT [dbo].[Contacts_NEW] ([emplid], [emcoid], [name], [conttp], [phone], [fax], [email], [auth], [ainits], [adate], [atime], [uinits], [udate], [utime]) 
VALUES (200, 113, N'Roger Federer', N'PENS', N'78415784156', NULL, N'nomail@nomail.co.uk', 1, N'MK785477', CAST(N'2016-08-17T00:00:00.000' AS DateTime), CAST(N'2068-02-07T00:00:00.000' AS DateTime), N'MK785477', CAST(N'2016-08-17T00:00:00.000' AS DateTime), CAST(N'2068-02-07T00:00:00.000' AS DateTime))
INSERT [dbo].[Contacts_NEW] ([emplid], [emcoid], [name], [conttp], [phone], [fax], [email], [auth], [ainits], [adate], [atime], [uinits], [udate], [utime]) 
VALUES (200, 114, N'Roger Federer', N'OFFI', N'78415784157', NULL, N'Yourmail@nomail.co.uk', 1, N'MK785477', CAST(N'2016-08-17T00:00:00.000' AS DateTime), CAST(N'2068-02-07T00:00:00.000' AS DateTime), N'MK785477', CAST(N'2016-08-17T00:00:00.000' AS DateTime), CAST(N'2068-02-07T00:00:00.000' AS DateTime))

给我更多的时间，我也许可以弄清楚，但就目前情况而言，我很沮丧。而且我不希望将其导出到excel中并手动处理所有记录。

我们将不胜感激，或者向正确的方向发展。

谢谢。

Answer 1

有条件的聚合可以很容易地解决这个问题。具有挑战性的部分是那些电子邮件，但并非没有。但是，在示例输出中，只有17列（商品代码1-4）。如果您需要调整以容纳五分之一，就很容易了。

select x.emplid
    , x.name
    , conttp = max(case when x.RowNum = 1 then x.conttp end)
    , conttp2 = max(case when x.RowNum = 2 then x.conttp end)
    , conttp3 = max(case when x.RowNum = 3 then x.conttp end)
    , conttp4 = max(case when x.RowNum = 4 then x.conttp end)
    , conttp5 = max(case when x.RowNum = 5 then x.conttp end)
    , conttp6 = max(case when x.RowNum = 6 then x.conttp end)
    , phone = max(case when x.RowNum = 1 then x.phone end)
    , phone2 = max(case when x.RowNum = 2 then x.phone end)
    , x.fax
    , email = max(case when x.RowNum = 1 then emails.email end)
    , email2 = max(case when x.RowNum = 2 then emails.email end)
    , emcoid1 = max(case when x.RowNum = 1 then x.emcoid end)
    , emcoid2 = max(case when x.RowNum = 2 then x.emcoid end)
    , emcoid3 = max(case when x.RowNum = 3 then x.emcoid end)
    , emcoid4 = max(case when x.RowNum = 4 then x.emcoid end)
from 
(
    select *
        , RowNum = ROW_NUMBER() over(partition by emplid order by emcoid)
    from Contacts c
) x
join
(
    select *
        , RowNum = ROW_NUMBER() over(partition by emplid order by (select null))
    from
    (
        select distinct email
            , emplid
        from Contacts
    ) a
) emails on emails.RowNum = x.RowNum
            and emails.emplid = x.emplid
group by x.emplid
    , x.name
    , x.fax