我必须检查字符串是否包含：字母数字，字母，数字，小写和大写字符

Question

def fun(s):
    for i in s:
        if i.isalnum():
            print("True")
        if i.isalpha():
            print("True")
        if i.isdigit():
            print("True")
        if i.isupper():
            print("True") 
        if i.islower():
            print("True")
s=input().split()
fun(s)

为什么即使在for循环中它也只能打印一次

Answer 1

if __name__ == '__main__':
    s = input()
    print(any(c.isalnum()  for c in s))
    print(any(c.isalpha() for c in s))
    print(any(c.isdigit() for c in s))
    print(any(c.islower() for c in s))
    print(any(c.isupper() for c in s))

使用任何函数为python 3更新代码，而无需使用其他函数

Answer 2

您正在将字符串方法应用于整个单词，而不是单个字符。您没有应用any或all条件来检查每个单词中的任何或 all 个字符是否满足每个条件。

例如，每个单词的条件为any：

def fun(s):
    for i in s:
        print('\n', i)
        if any(letter.isalnum() for letter in i):
            print('Alnum', True)
        if any(letter.isalpha() for letter in i):
            print('Alpha', True)
        if any(letter.isdigit() for letter in i):
            print('Digit', True)
        if any(letter.isupper() for letter in i):
            print('Upper', True) 
        if any(letter.islower() for letter in i):
            print('Lower', True)

s = input().split()
fun(s)

示例结果：

One test 123

 One
Alnum True
Alpha True
Upper True
Lower True

 test
Alnum True
Alpha True
Lower True

 123
Alnum True
Digit True

Answer 3

如果要检查整个字符串是否包含那些不同的字符类型，则实际上不必遍历整个字符串。您只能使用any关键字。

def fun(s):
    if any(letter.isalnum() for letter in s):
        print("Is alphanumeric")
    if any(letter.isalpha() for letter in s):
        print("Is alpha")
    if any(letter.isdigit() for letter in s):
        print("Is digit")
    if any(letter.isupper() for letter in s):
        print("Is upper")
    if any(letter.islower() for letter in s):
        print("Is lower")

s=str(input())
fun(s)

Answer 4

string = input()

print (any(c.isalnum() for c in s))
print (any(c.isalpha() for c in s))
print (any(c.isdigit() for c in s))
print (any(c.islower() for c in s))
print (any(c.isupper() for c in s))

Answer 5

if __name__ == '__main__':
    s = input()
    print (any([c.isalnum() for c in s]))
    print (any([c.isalpha() for c in s]))
    print (any([c.isdigit() for c in s]))
    print (any([c.islower() for c in s]))
    print (any([c.isupper() for c in s]))

Answer 6

if __name__ == '__main__':
    s = input()
    print (any([c.isalnum() for c in s]))
    print (any([c.isalpha() for c in s]))
    print (any([c.isdigit() for c in s]))
    print (any([c.islower() for c in s]))
    print (any([c.isupper() for c in s]))

使用 any 关键字，检查字母表中的所有字母并返回 true I 任何一个满足它的字母。

Answer 7

any() 函数是 Python 中的一个内置函数，它返回 true 如果给定可迭代对象的任何元素 （列表、字典、元组、集合等）为 True，否则返回 False。

if len(s) > 0 and len(s) < 1000:
    print(any([i.isalnum() for i in s]))
    print(any([i.isalpha() for i in s]))
    print(any([i.isdigit() for i in s]))
    print(any([i.islower() for i in s]))
    print(any([i.isupper() for i in s]))

Answer 8

if __name__ == '__main__':
    s = input()
    a1,a2,a3,a4,a5=False,False,False,False,False
  
    for i in s:
        a1=True if i.isalnum()==True else a1
        a2=True if i.isalpha()==True else a2
        a3=True if i.isdigit()==True else a3
        a4=True if i.islower()==True else a4
        a5=True if i.isupper()==True else a5
    
    print(a1,a2,a3,a4,a5,sep="\n")