Question

我有一个类在我的Web应用程序中注册用户，构造函数进行基本的验证和清理。问题是，当我尝试转储值时，它们都是空字符串。以下是RegisterUser类中的代码：

<?php

class RegisterUser {

    public $firstName = ""; 
    public $lastName = ""; 
    public $email = ""; 
    public $password = "";

    // Validating registration data
    function _construct($firstName, $lastName, $email, $password) {
        $firstName = filter_var($firstName, FILTER_SANITIZE_STRING);
        $lastName = filter_var($lastName, FILTER_SANITIZE_STRING);
        $email = filter_var($email, FILTER_SANITIZE_EMAIL);
        $password = filter_var($password, FILTER_SANITIZE_STRING);
        if (empty($firstName) || !preg_match("^[A-Za-z.\s_-]+$", $firstName)) {
            throw new Exception("First name not filled in or is invalid.");
        }
        if (empty($lastName) || !preg_match("^[A-Za-z.\s_-]+$", $lastName)) {
            throw new Exception("Last name not filled in or is invalid.");
        }
        if (empty($email) || !filter_var($email, FILTER_VALIDATE_EMAIL)) {
            throw new Exception("Email not filled in or is invalid.");
        }
        if (empty($password) || !preg_match("^(?=.*[a-z])(?=.*[A-Z])(?=.*[0-9])(?=.*[!@#\$%\^&\*]).{8,}", $password)) {
            throw new Exception("Password not filled in or is invalid.");
        }
        $this->firstName = $firstName;
        $this->lastName = $lastName;
        $this->email = $email;
        $this->password = $password;
    }

}

这是我在index.php文件中的调用方式：

$register = new RegisterUser($registerFormData["firstName"], $registerFormData["lastName"], $registerFormData["email"], $registerFormData["password"]);<br>

我还完成了var_dump($registerFormData)，它返回了正确提交的值。

这是简短的版本：
为什么当我尝试var_dump($register)时，我会得到所有空白值吗？

Answer 1

您必须将两个下划线与构造函数一起使用，如下所示：

function __construct($firstName, $lastName, $email, $password) {

有关构造函数here

的更多信息

PHP类构造函数将所有值设置为null

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