大家好,我真的很接近完成这个但是我的for循环遇到了问题。我需要我的程序让用户输入'w'或'h'让他们输入新的体重或身高。当他们做我的循环似乎停止由于某种原因。
package Assignments;
import java.util.*;
public class assignment3 {
public static void main(String[] args) {
//Scanner
Scanner stdIn = new Scanner(System.in);
//Variables
final double METERS_TO_CM = 100; // The constant to convert meters to centimeters
final double BSA_CONSTANT = 3600; // The constant to divide by for bsa
double bmi; // Body Mass Index
double weight; // Weight in kilograms
double height; // Height in meters
String classification; // Classifies the user into BMI categories
double bsa; // Body surface area
System.out.print("Welcome to the BMI and BSA Calculator to begin enter weight in kilograms.");
weight = stdIn.nextDouble();
System.out.print("Enter height in meters: ");
height = stdIn.nextDouble();
bmi = weight/(height*height);
bsa = Math.sqrt(((height*METERS_TO_CM)*weight)/BSA_CONSTANT);
if (bmi < 18.5)
{
classification = "Underweight";
}
else if (bmi < 25)
{
classification = "Normal";
}
else if (bmi < 30)
{
classification = "Overweight";
}
else
{
classification = "Obese";
}
System.out.println("Choose Options below to set height and weight");
System.out.println("Your classification is: " + classification);
System.out.println("(H)eight: " + height + " meters");
System.out.println("(W)eight: " + weight + " kilograms");
System.out.printf("BMI: %.1f\n", bmi);
System.out.printf("BSA: %.2f\n", bsa);
System.out.println("(Q)uit");
do {
String response = stdIn.next();
if (response.charAt(0)== 'w')
{
System.out.println("Enter new weight: ");
weight = stdIn.nextDouble();
System.out.println("Choose Options below to set height and weight");
System.out.println("Your classification is: " + classification);
System.out.println("(H)eight: " + height + " meters");
System.out.println("(W)eight: " + weight + " kilograms");
System.out.printf("BMI: %.1f\n", bmi);
System.out.printf("BSA: %.2f\n", bsa);
System.out.println("(Q)uit");
}
else if (response.charAt(0) == 'h')
{
System.out.println("Enter new height: ");
height = stdIn.nextDouble();
System.out.println("Choose Options below to set height and weight");
System.out.println("Your classification is: " + classification);
System.out.println("(H)eight: " + height + " meters");
System.out.println("(W)eight: " + weight + " kilograms");
System.out.printf("BMI: %.1f\n", bmi);
System.out.printf("BSA: %.2f\n", bsa);
System.out.println("(Q)uit");
}
else if (response.charAt(0)!= 'w')
{
System.out.println("That is not a valid choice try again");
response = stdIn.next();
}
else if (response.charAt(0)!= 'h')
{
System.out.println("that is not a valid choise try again");
response = stdIn.next();
}
} while (stdIn.next().compareToIgnoreCase("q")!=0);
}
}
答案 0 :(得分:3)
通过执行stdIn.next().compareToIgnoreCase("q")!=0
,您要求计算机从STDIN缓冲区中提取下一个值。这意味着在您完成处理后,While循环正在等待数据从STDIN进入,然后才决定继续处理。你最好让while循环连续运行while( true ) { ... }
并检查输入值(当你要求H或W时)检查它是否是q。如果是,则让程序退出。
答案 1 :(得分:0)
循环是什么? - 没关系,因为它已被纠正
我确实看到了您的Scanner对象的潜在问题,但因为它没有处理行尾令牌,您可能想要调用stdIn.nextLine();每次调用stdIn.next()之后;或者stdIn.nextDouble();,这样就可以正确处理行尾字符。
答案 2 :(得分:0)
你在太多地方调用stdIn.next()
:在循环开始时,在循环终止测试中,以及在最后两个分支中(顺便说一句,它们都应该由一个分支替换) else { ... }
)。 (循环是一个do循环,顺便说一下,不是for循环。)
另一个问题是使用Scanner混合输入并使用System.out输出。我建议在尝试通过扫描程序进行任何输入之前调用System.out.flush()。