在Kotlin中自定义实现回调以进行改造

时间:2018-07-12 12:50:45

标签: android kotlin retrofit retrofit2

我最近开始使用Kotlin进行android开发,并且遇到了一些小问题,这些问题可以通过使用文档解决,但是使用Retrofit Callback实施时,我遇到了问题。我在Java中使用了Retrofit回调的自定义实现:

public abstract class RemoteCallback<T> implements Callback<T> {
@Override
public final void onResponse(Call<T> call, Response<T> response) {

    switch (response.code()) {
        case HttpsURLConnection.HTTP_OK:
        case HttpsURLConnection.HTTP_CREATED:
        case HttpsURLConnection.HTTP_ACCEPTED:
        case HttpsURLConnection.HTTP_NOT_AUTHORITATIVE:
            if (response.body() != null) {
                onSuccess(response.body());
            }
            break;
        case HttpURLConnection.HTTP_UNAUTHORIZED:
            onUnauthorized();
            break;
        default:
            onFailed(new Throwable("Default " + response.code() + " " + response.message()));
    }
}

@Override
public final void onFailure(Call<T> call, Throwable t) {
    onFailed(t);
}

public abstract void onSuccess(T responseBody);

public abstract void onUnauthorized();

public abstract void onFailed(Throwable throwable);}

我在Kotlin Project中使用了相同的类,该类将Java代码转换为Kotlin代码

abstract class RemoteCallback<T> : Callback<T> {
override fun onResponse(call: Call<T>, response: Response<T>) {

    when (response.code()) {
        HttpsURLConnection.HTTP_OK,
        HttpsURLConnection.HTTP_CREATED,
        HttpsURLConnection.HTTP_ACCEPTED,
        HttpsURLConnection.HTTP_NOT_AUTHORITATIVE ->
            if (response.body() != null)
            onSuccess(response.body())
        HttpURLConnection.HTTP_UNAUTHORIZED -> onUnauthorized()
        else -> onFailed(Throwable("Default " + response.code() + " " + response.message()))
    }
}

override fun onFailure(call: Call<T>, t: Throwable) {
    onFailed(t)
}

abstract fun onSuccess(responseBody: T)

abstract fun onUnauthorized()

abstract fun onFailed(throwable: Throwable)}

问题是当我调用onSucess(response.body())时,它说“不可能将智能强制转换为'T',因为'response.body()'是一个复杂的表达式” Problem 请指导我如何解决

2 个答案:

答案 0 :(得分:2)

您正在将Nullable值作为参数发送到NonNull函数。因此,您遇到了这个问题。您可以这样:

interface RemoteCallback<T> : Callback<T> {
    override fun onResponse(call: Call<T>?, response: Response<T>?) {
        when (response?.code()) {
            HttpsURLConnection.HTTP_OK,    
            HttpsURLConnection.HTTP_CREATED,
            HttpsURLConnection.HTTP_ACCEPTED,
            HttpsURLConnection.HTTP_NOT_AUTHORITATIVE ->
                response.body()?.apply { onSuccess(this) }
            HttpURLConnection.HTTP_UNAUTHORIZED -> onUnauthorized()
            else -> onFailed(Throwable("Default " + response?.code() + " " + response?.message()))
        }
    }

    override fun onFailure(call: Call<T>?, t: Throwable?) {
        // handle error mechanism
        t?.apply { onFailed(this) }    
    }
    fun onSuccess(responseBody: T)
    fun onUnauthorized()
    fun onFailed(throwable: Throwable)
}

或者,您可以只使用onSuccess(responseBody: T?)并且您的代码应该可以工作

答案 1 :(得分:1)

我的项目中有非常相似的实现。请按照以下步骤尝试

abstract class RemoteCallback: Callback<ResponseBody> {
    override fun onFailure(call: Call<ResponseBody>?, t: Throwable?) {
        onFailed(t)
    }

    override fun onResponse(call: Call<ResponseBody>?, response: Response<ResponseBody>?) {
        when (response.code()) {
            HttpsURLConnection.HTTP_OK,
            HttpsURLConnection.HTTP_CREATED,
            HttpsURLConnection.HTTP_ACCEPTED,
            HttpsURLConnection.HTTP_NOT_AUTHORITATIVE ->
                if (response.body() != null)
                onSuccess(response.body())
            HttpURLConnection.HTTP_UNAUTHORIZED -> onUnauthorized()
            else -> onFailed(Throwable("Default " + response.code() + " " + response.message()))
        }
    }

    abstract fun onUnauthorized()

    abstract fun onFailed(throwable: Throwable)
}

对我来说很好