Question

很抱歉再次发表有关该主题的文章。总共有4页的结果，因此很难磨合特定的解决方案。

谁能看到此SQL的问题吗？

SELECT evntmst_id, count(evntmst_id) AS idcount
FROM evntcond 
WHERE EVNTMST_ID NOT IN (
    SELECT DISTINCT c.EVNTMST_ID 
    FROM evntcond c 
    LEFT JOIN evntmst m 
    ON c.EVNTMST_ID = m.EVNTMST_ID
    WHERE m.EVNTMST_TYPE IN (1, 7) -- Group or Subset
    AND m.EVNTMST_ID IS NOT NULL   -- remove data integrity issues
    GROUP BY c.EVNTMST_ID
    ORDER BY c.EVNTMST_ID
)
GROUP BY EVNTMST_ID
ORDER BY count(evntmst_id) Desc

这产生 ORA-00907: missing right parenthesis

如果我使用嵌套的SELECT DISTINCT并将其替换为1,2，则一切正常。

SELECT evntmst_id, count(evntmst_id) AS idcount
FROM evntcond 
WHERE EVNTMST_ID NOT IN (
    1,2
)
GROUP BY EVNTMST_ID
ORDER BY count(evntmst_id) Desc

如果我自己运行嵌套查询，则一切正常。

SELECT DISTINCT c.EVNTMST_ID 
FROM evntcond c 
LEFT JOIN evntmst m 
ON c.EVNTMST_ID = m.EVNTMST_ID
WHERE m.EVNTMST_TYPE IN (1, 7) -- Group or Subset
AND m.EVNTMST_ID IS NOT NULL   -- remove data integrity issues
GROUP BY c.EVNTMST_ID
ORDER BY c.EVNTMST_ID

Oracle有什么功能。这是错误吗？

Answer 1

这似乎太复杂了。我想你打算：

SelectionChanged

这会过滤出SELECT c.evntmst_id, COUNT(c.evntmst_id) AS idcount FROM evntcond c WHERE NOT EXISTS (SELECT 1 FROM evntmst m WHERE m.EVNTMST_ID = c.EVNTMST_ID AND m.EVNTMST_TYPE IN (1, 7) ) GROUP BY EVNTMST_ID ORDER BY count(evntmst_id) DESC;，其中有相应的“ 1”或“ 7”记录。

我应该补充一点，您的查询中没有明显的语法错误。

ORA-00907：缺少右括号-嵌套选择NOT IN

1 个答案: