我想做什么：

Question

我想做什么：

1。创建带有选择文件选项的文件对话框 1.1第一个选择文件的按钮读取其位置 ->可以通过下面的链接提供解决方案

from tkinter import *
from tkinter.filedialog import askopenfilename
from tkinter.messagebox import showerror

class MyFrame(Frame):
    def __init__(self):
        Frame.__init__(self)
        self.master.title("Example")
        self.master.rowconfigure(5, weight=1)
        self.master.columnconfigure(5, weight=1)
        self.grid(sticky=W+E+N+S)

        self.button = Button(self, text="Browse", command=self.load_file, width=10)
        self.button.grid(row=1, column=0, sticky=W)

    def load_file(self):
        fname = askopenfilename(filetypes=(("Template files", "*.tplate"),
                                           ("HTML files", "*.html;*.htm"),
                                           ("All files", "*.*") ))
        if fname:
            try:
                print("""here it comes: self.settings["template"].set(fname)""")
            except:                     # <- naked except is a bad idea
                showerror("Open Source File", "Failed to read file\n'%s'" % fname)
            return


if __name__ == "__main__":
    MyFrame().mainloop()

1.2第二个按钮开始处理 ->通过向开始添加另一个按钮 ->添加带有参数 process_it 的函数。 -> 因此带有参数的函数调用不适用于我的代码

from tkinter import *
from tkinter.filedialog import askopenfilename
from tkinter.messagebox import showerror

class MyFrame(Frame):
    def __init__(self):
        Frame.__init__(self)
        self.master.title("Example")
        self.master.rowconfigure(5, weight=1)
        self.master.columnconfigure(5, weight=1)
        self.grid(sticky=W+E+N+S)

        self.button = Button(self, text="Browse", command=self.load_file, width=10)
        self.button.grid(row=1, column=0, sticky=W)

        #new code added by me:
        self.button = Button(self, text="Start Now", command=self.process_it(arg_1), width=10)
        self.button.grid(row=2, column=0, sticky=W)

    def load_file(self):
        #new code added by me:
        global arg1 

        fname = askopenfilename(filetypes=(("Template files", "*.tplate"),
                                           ("HTML files", "*.html;*.htm"),
                                           ("All files", "*.*") ))
        #new code added by me:
        arg_1 = fname

        if fname:
            try:
                print("""here it comes: self.settings["template"].set(fname)""")
            except:                     # <- naked except is a bad idea
                showerror("Open Source File", "Failed to read file\n'%s'" % fname)
            return

    # new function added by me:
    def process_it(self, arg_1):
        #use the arg_1 further, example :
        print(arg_1)    


if __name__ == "__main__":
    MyFrame().mainloop()

Answer 1

您可以编写工厂函数来传递一些参数。

def command_factory(arg_1):
    def process_it():
        print(arg_1)
    return process_it

使用

Button(self, text="Start Now", command=command_factory(arg_1))

或者只是

Button(self, text="Start Now", command=lambda: self.proccess_it(arg_1))

但是在这种情况下，您需要确保arg_1变量没有更改以避免后期绑定。

如何从“ tkinter” python包的“按钮”函数中调用带有参数的函数？

我想做什么：

1 个答案: