Question

如何从本《守则》中按性别或身体状况按省获取男女总数？

SELECT sv.province_name, sv.district_name,
          sum(sexual_female_less_10) as sexual_female_less_10,
          sum(sexual_female_10_14) as sexual_female_10_14,
          sum(sexual_female_15_19) as sexual_female_15_19,
          sum(sexual_female_20_24) as sexual_female_20_24,
          sum(sexual_female_25_plus) as sexual_female_25_plus,
          sum(sexual_male_less_10) as sexual_male_less_10,
          sum(sexual_male_10_14) as sexual_male_10_14,
          sum(sexual_male_15_19) as sexual_male_15_19,
          sum(sexual_male_20_24) as sexual_male_20_24,
          sum(sexual_male_25_plus) as sexual_male_25_plus,
          sum(physical_female_less_10) as physical_female_less_10,
          sum(physical_female_10_14) as physical_female_10_14,
          sum(physical_female_15_19) as physical_female_15_19,
          sum(physical_female_20_24) as physical_female_20_24,
          sum(physical_female_25_plus) as physical_female_25_plus,
          sum(physical_male_less_10) as physical_male_less_10,
          sum(physical_male_10_14) as physical_male_10_14,
          sum(physical_male_15_19) as physical_male_15_19,
          sum(physical_male_20_24) as physical_male_20_24,
          sum(physical_male_25_plus) as physical_male_25_plus

   FROM vw_experiencedphysicalviolence pv
   JOIN vw_experiencedsexualviolence sv ON pv.id = sv.id
   GROUP BY sv.district_name, sv.province_name

Answer 1

一些细节。

在GROUP BY子句中，您将按地区和省进行分组。在您的问题中，指定省。如果正确的话，您的分组依据应该像这样GROUP BY sv.province_name
发布SQL问题时，它有助于标记您正在使用的数据库引擎。在这种情况下，答案很可能包含在ANSI标准中。但是，更高级的查询可能会依赖于供应商特定的SQL实现。
如果要按省汇总男性和女性的总数，则可以对各列求和，然后对合计值求和。

请参见下面的示例代码：

SELECT 
sv.province_name, 
sv.district_name, -- Remove if you remove from group by clause
sum(sexual_female_less_10) +
sum(sexual_female_10_14) +,
sum(sexual_female_15_19) +
sum(sexual_female_20_24) +
sum(sexual_female_25_plus) AS total_f_sexual_violence,  
sum(physical_female_less_10) +
sum(physical_female_10_14) +
sum(physical_female_15_19) +
sum(physical_female_20_24) +
sum(physical_female_25_plus) AS total_f_physical_violence,  
sum(sexual_male_less_10) +
sum(sexual_male_10_14) +
sum(sexual_male_15_19) +
sum(sexual_male_20_24) +
sum(sexual_male_25_plus) AS total_m_sexual_violence,
sum(physical_male_less_10) +
sum(physical_male_10_14) +
sum(physical_male_15_19) +
sum(physical_male_20_24) +
sum(physical_male_25_plus) AS total_f_physical_violence
FROM vw_experiencedphysicalviolence pv
JOIN vw_experiencedsexualviolence sv ON pv.id = sv.id
GROUP BY 
sv.district_name, -- Per your question you may not want to group by district_name  
sv.province_name

Answer 2

您可以尝试使用OVER子句。

即：

SELECT DISTINCT
    sv.province_name,
    sv.district_name,
    sum(sexual_female_less_10) OVER (partition by sv.province_name, sv.district_name) as District_sexual_female_less_10,
    sum(sexual_female_less_10) OVER (partition by sv.province_name) as Province_sexual_female_less_10,
...
FROM vw_experiencedphysicalviolence pv
JOIN vw_experiencedsexualviolence sv ON pv.id = sv.id

有关更多信息：https://docs.microsoft.com/en-us/sql/t-sql/functions/sum-transact-sql?view=sql-server-2017

获取总数：如何从本《守则》中按性别或身体状况按省获取男女总数？

2 个答案: