Question

我有表Users，部门，文件和shareFiles。我想编写一个查询，当用户尝试向另一个用户发送文件时，共享功能应该捕获文件的标题以及发送文件的用户部门，该文件将保存在shareFiles表中。

用户表：id，department_id
文件表：id，title，user_id
部门表格：id，name
ShareFiles表：title，file，department_id，user_id，sender，to

以下是我在分享功能中所做的事情

public function shareFile(Request $request)
    {

        $userfile = new UserFile();
        $userfile->sender = \Auth::user()->username;
        $userfile->to = $request->user;
        $userfile->title = File::select('title')->where(['user_id' => \Auth::user()->id])
        ->orWhere('id','=','user_id')->get();

        $userfile->department = DB::table('departments')->select('departments.name')
        ->join('users','departments.id','=','users.department_id')
        ->where(['users.id' => \Auth::user()->id])
        ->get();

        $userfile->user_id = \Auth::user()->id;
        $userfile->save();
        Session::flash('message','File successfully shared !!');
        return redirect('/hr/document');
    }

Answer 1

尝试此代码：-

For title selection:

$file = File::select('title')->where(['user_id' => \Auth::user()->id]) ->orWhere('id','=','user_id')->first();

For Department:

$dept = DB::table('departments')->select('departments.name') ->join('users','departments.id','=','users.department_id') ->where(['users.id' => \Auth::user()->id]) ->first();

注意：您也可以使用value（）和pluck（）（如果需要值数组）来代替select（）。

我该如何用laravel雄辩地编写此查询

1 个答案: