我想访问laravel常量文件中的服务器名称,但是我正面临Undefined index: SERVER_NAME
,在运行此条件时会出现错误
已经定义了恒定的APIURL
这是我的constant.php
if((isset($_SERVER['SERVER_NAME'])) && ($_SERVER['SERVER_NAME'] == 'onboarding.posplus.co.za')){
define('APIURL', 'https://example.com/bib/public/api/v1/');
define('BIBURL','https://example.com/bib/public/assets/');
define('IS_VERIFY',false);
define('BUSINESS_URL','https://example.com/api/app/business/validate');
define('X_API_KEY','234242');
define('SECRET','dsadad');
define('IS_HTTPS',FALSE);
define('DOMAIN','pro');
}else{
define('APIURL', 'https://example.com/public/bib/public/api/v1/');
define('BIBURL','https://example.com/public/bib/public/assets/');
define('IS_VERIFY',true);
define('BUSINESS_URL','example.com/api/v1/app/business/validate');
define('X_API_KEY','sdsadss');
define('SECRET','67889999999');
define('IS_HTTPS',TRUE);
define('DOMAIN','qa');
}
define('USERNAME','1n@.com');
请帮助我。
谢谢
答案 0 :(得分:2)
您应该首先检查应用程序是从控制台运行还是通过http请求运行:
if (!app()->runningInConsole()) {
// not running in console, must be a request...
$name = request()->server('SERVER_NAME');
// your code here ...
} else {
// console invoked (e.g. artisan)
$name = gethostname(); // or php_uname('n') for older PHP versions
// your code here ...
}
关于APIURL
被定义的错误,您需要首先检查是否已定义,然后再定义:
if (!defined('APIURL')) {
define('APIURL', 'http://example.com');
}
答案 1 :(得分:0)
测试此代码:
if(request()->server('SERVER_NAME') == 'onboarding.posplus.co.za')){
if (!defined('apiurl')) {
define('apiurl', "https://example.com/bib/public/api/v1/'");
}
$biburl = "https://example.com/bib/public/assets/";
$isVerify = false;
$businessUrl = "https://www.example.com/api/app/business/validate";
$x_api_key = "234324";
$secret = "sdfsfsdf";
$isHttp = FALSE;
$domain = "pro";
}else{
if (!defined('apiurl')) {
define('apiurl', "https://example.com/bib/public/assets/");
}
$biburl = "https://example.com/bib/public/assets/";
$biburl = "https://example.com/public/bib/public/assets/";
$isVerify = true;
$businessUrl = "https://example.com/api/v1/app/business/validate";
$x_api_key = "q12313";
$secret = "123123asdasd";
$isHttp = TRUE;
$domain = "qa";
}