我正在尝试使用if-constexpr进行检查,但是遇到类似错误
期望'('在'constexpr'之前
'else',而前面没有'if'“
到目前为止,我检查我的代码没有问题
我的编译标志是g ++ -std = c ++ 17 main.cpp
#include <iostream>
template<typename T, typename Comp = std::less<T> >
struct Facility
{
template<T ... list>
struct List
{
static void print()
{
std::cout<<"\""<<"Empty List"<<"\""<<"\n";
}
};
template<T head,T ... list>
struct List<head,list...>
{
static void print()
{
std::cout<<"\"" << head;
((std::cout << " " << list), ...);
std::cout<<"\""<<"\n";
}
};
template<unsigned N,typename AA>
struct RemoveFirst{};
template<unsigned N,T head,T ... Rest>
struct RemoveFirst<N,List<head,Rest...>>
{
struct result
{
static void print()
{
if constexpr (N == head)
{
std::cout<<"";
}
else
{
std::cout<<"\""<<head;
((std::cout << " " << Rest), ...);
std::cout<<"\""<<"\n";
}
}
};
};
};
template<int ... intlist>
using IntList = typename Facility<int>::List<intlist...>;
int main()
{
using IntFacility = Facility<int>;
using List = IntList<2, 8, 2, 3, 5, 10, 8, 5>;
}
答案 0 :(得分:8)
不支持C ++ 17最终版本的较旧版本的GCC(最高6.x)会给出该错误,因为它们将constexpr
识别为关键字,但不理解constexpr-if构造。确保您的GCC是版本7或更高版本。