Question

我目前正在学习“复合设计模式”及其在Laravel中的使用，我想不通。

假设我有一个Things的列表。这些东西具有相同的基本属性，因此，例如，如果我为每个Things创建一个模型，我将得到类似的信息：

Thing1.php：

<?php
class Thing1 extends Model {
    protected $title;
    protected $description;

    protected $fillable = [
      'title',
      'description'
    ];        

    public function __construct(string $title, string $description) {
        $this->title = $title;
        $this->description = $description;
    }

    public function getTitle(): string {
        return $this->title;
    }

    public function getDescription(): string {
        return $this->description;
    }

    public function setTitle(string $title) {
        $this->title = $title;
    }

    public function setDescription(string $description) {
        $this->description = $description;
    }
}

Thing2.php：

<?php
class Thing2 extends Model {
    protected $title;
    protected $description;
    protected $totalPrice = null;
    protected $parent_id;     

    protected $fillable = [
      'title',
      'description',
      'totalPrice',
      'parent_id'
    ];        

    public function __construct(string $title, string $description, int $totalPrice = null, int $parent_id) {
        $this->title = $title;
        $this->description = $description;
        $this->totalPrice = $totalPrice;
        $this->parent_id = $parent_id;
    }

    public function getTitle(): string {
        return $this->title;
    }

    public function getDescription(): string {
        return $this->description;
    }

    public function getTotalPrice(): int {
        return $this->totalPrice;
    }

    public function setTitle(string $title) {
        $this->title = $title;
    }

    public function setDescription(string $description) {
        $this->description = $description;
    }

    public function setTotalPrice(int $totalPrice) {
        if(!is_null($totalPrice))
            $this->totalPrice = $totalPrice;
    }

    public function setParentId(int $parent_id) {
        $this->parent_id = $parent_id;
    }
}

Thing3.php：

<?php
class Thing3 extends Model {
    protected $title;
    protected $description;
    protected $totalPrice;

    protected $fillable = [
      'title',
      'description',
      'totalPrice'
    ];        

    public function __construct(string $title, string $description, int $totalPrice) {
        $this->title = $title;
        $this->description = $description;
        $this->totalPrice = $totalPrice;
    }

    public function getTitle(): string {
        return $this->title;
    }

    public function getDescription(): string {
        return $this->description;
    }

    public function getTotalPrice(): int {
        return $this->totalPrice;
    }

    public function setTitle(string $title) {
        $this->title = $title;
    }

    public function setDescription(string $description) {
        $this->description = $description;
    }

    public function setTotalPrice(int $totalPrice) {
        $this->totalPrice = $totalPrice;
    }
}

但是现在使用Composite Design Pattern，我的想法是创建一个名为ThingComposite.php的模型，该模型将包含以下基本方法：

<?php
abstract class ThingComposite extends Model {
    public function getTitle(): string;
    public function getDescription(): string;
    public function setTitle(string $title);
    public function setDescription(string $description); 
}

以及将扩展ThingComposite的3个事物模型。

但是我想不出几件事，希望您能对我有所帮助：

如果所有Things扩展了一个类，该类扩展了ThingComposite并与一个表有关系，那么我将如何在Things之间进行“仲裁”？ / p>
属性：totalPrice和parent_id是“特殊键”，由于它们对于特定模型是唯一的，因此不会显示为基本属性/方法。那么我将如何在模型中表示它呢？怎样在表格中表示呢？

我听说过MySQL中的JSON，也许这是解决方案？
如果我想通过自己的对象显示每个Thing，但使用与ThingComposite类相关的相同“复合表”，则如何构建控制器？

如何创建“综合模型”并迁移到“综合表”

0 个答案: