Question

在接收多部分/表单数据POST请求期间，我遇到了问题，但是我无法在我的身体内部出现问题。发送请求后，服务器会用此错误答复我

MIME多部分流的意外结尾。 MIME分段消息不是完成。

关注请求的正文。

-------BoundaryNg6f698dj968io34abg32rfa3

Content-Disposition: form-data; name="json"; filename="json"; Content-Type:application/json

{"key":"value","key":"value","key":"value","key":"value","key":"value"}

-------BoundaryNg6f698dj968io34abg32rfa3

Content-Disposition: form-data; name="style"; filename="style.css"; Content-Type:text/css

body {
    width: 100%;
    margin: 0;
    padding: 0;
    [etc etc]}


-------BoundaryNg6f698dj968io34abg32rfa3

Content-Disposition: form-data; name="play_circle"; filename="play_circle.png"; Content-Type:image/png


[Image]

-------BoundaryNg6f698dj968io34abg32rfa3

在我看来，所有的身体看起来都是正确的，但是我很累，也许有人可以帮助我解决我的问题？

@edit

下面您将看到我如何构建multypart车身：

此部分构建Css和Json部分。

public byte[] bodyBuilder()
        {
            byte[] bodyAtt = new byte[1];
            StringBuilder sb = new StringBuilder();
            foreach (PostData p in postData)
            {
                sb.Append(string.Format("\r\n{0}", boundary));
                sb.AppendLine("\r\n");
                sb.Append(string.Format("Content-Disposition: form-data; name=\"{0}\"; filename=\"{1}\"; Content-Type:{2}", p.Name,p.FileName, p.Type));
                sb.AppendLine("\r\n");
                sb.Append(string.Format("{0}\r\n", p.Value));
            }

            bodyAtt = encoding.GetBytes(sb.ToString());
            if (content_Type.Contains("multipart/form-data"))
            {
                bodyAtt = Combine(bodyAtt, setAttachPostData());
            }

            var str = Encoding.Default.GetString(bodyAtt);

            string pathFile = Path.Combine(Environment.GetFolderPath(Environment.SpecialFolder.Desktop), "Log.txt");
            File.WriteAllText(pathFile, str);

            return bodyAtt;
        }

这是用于图像。

public byte[] setAttachPostData()
        {

            byte[] bodyAtt = new byte[1];

            foreach (PostDataParam p in postDataParams)
            {
                StringBuilder sb = new StringBuilder();
                sb.AppendLine("\r\n");
                sb.Append(string.Format("{0}", boundary));
                sb.AppendLine("\r\n");
                sb.AppendLine(string.Format("Content-Disposition: form-data; name=\"{0}\"; filename=\"{1}\"; Content-Type:{2}", p.Name, p.FileName, p.Type));
                sb.AppendLine("\r\n");
                bodyAtt = Combine(bodyAtt, encoding.GetBytes(sb.ToString()));                     bodyAtt = Combine(bodyAtt, p.data);
            }
            bodyAtt = Combine(bodyAtt, encoding.GetBytes(string.Format("\r\n\r\n{0}\r\n", boundary)));

            return bodyAtt;
        }

和Combine方法很简单：

 public static byte[] Combine(byte[] first, byte[] second)
        {
            byte[] ret = new byte[first.Length + second.Length];
            Buffer.BlockCopy(first, 0, ret, 0, first.Length);
            Buffer.BlockCopy(second, 0, ret, first.Length, second.Length);
            return ret;
        }

Answer 1

我已经使用这部分代码解决了这个问题：

public async Task<string> BuildMultipartAsync()
        {
            try
            {
                MultipartFormDataContent form = new MultipartFormDataContent();

                foreach (PostData p in postData)
                {
                    form.Add(new StringContent(p.Value), p.Name, p.FileName);
                }

                foreach (PostDataParam p in postDataParams)
                {
                    form.Add(new ByteArrayContent(p.data, 0, p.data.Length), p.Name, p.FileName);
                }

                HttpResponseMessage response = await httpClient.PostAsync(URLCall, form);

                response.EnsureSuccessStatusCode();
                httpClient.Dispose();
                string sd = response.Content.ReadAsStringAsync().Result;
                return sd;
            }catch (Exception e)
            {
                return e.Message;
            }
        }

引用自：

How to upload file to server with HTTP POST multipart/form-data

希望可以提供帮助。

C＃multipart / form-data MIME多部分流的意外结尾

1 个答案: