我在R-Shiny应用程序中使用subplot函数从plotly绘制两个图(一个在另一个图下)。图例对于两个图形都是通用的,这意味着我只有一列,所有图例都组装在一起。
我想在子图中分别在每个图形附近放置图例。我如何获得它?
p1 <-
iris%>%
group_by(Species)%>%
plot_ly(x=~Sepal.Length, color= ~Species, legendgroup=~Species)%>%
add_markers(y= ~Sepal.Width)
p2 <-
iris%>%
group_by(Species)%>%
plot_ly(x=~Sepal.Length, color= ~Species, legendgroup=~Species)%>%
add_markers(y= ~Sepal.Width)
subplot(p1,p2, nrows = 2, shareX = T, shareY = F, titleX = T, titleY = T)
答案 0 :(得分:1)
根据this,目前尚无法实现。这远非完美的破解方法,但如果您愿意,类似的方法可能是可行的-
使用n
来确定您的着色变量中唯一元素的数量。
library(plotly)
n <- 3L
clrs <- colorRampPalette(
c(rgb(r = 198, g = 89, b = 17, maxColorValue = 255), '#267dff', 'black')
)(n)
annotations <- c('setosa', 'versicolor', 'virginica')
y_annotation <- seq(0.4, 0.6, length.out = n)
p1 <-
iris %>%
group_by(Species) %>%
plot_ly(x = ~Sepal.Length, color = ~Species, showlegend = FALSE, colors = clrs) %>%
add_markers(y= ~Sepal.Width) %>%
layout(margin = list(r = 100))
for (i in seq_along(annotations)) {
p1 <- add_annotations(
p = p1, text = annotations[i], font = list(color = clrs[i]),
x = 1.05, y = y_annotation[i], xref = 'paper', yref = 'paper',
showarrow = FALSE, xanchor = 'left'
)
}
p2 <-
iris%>%
group_by(Species) %>%
plot_ly(x = ~Sepal.Length, color = ~Species, showlegend = FALSE, colors = clrs) %>%
add_markers(y = ~Sepal.Width) %>%
layout(margin = list(r = 100))
for (i in seq_along(annotations)) {
p2 <- add_annotations(
p = p2, text = annotations[i], font = list(color = clrs[i]),
x = 1.05, y = y_annotation[i], xref = 'paper', yref = 'paper',
showarrow = FALSE, xanchor = 'left'
)
}
subplot(p1, p2, nrows = 2, shareX = T, shareY = F, titleX = T, titleY = T)
这将导致如下图所示。