如果列有两个值，则仅选择一个

Question

我有以下数据：

如果某人每个日期同时具有“ Ramping”和“ Ramped”状态，那么我希望结果仅返回每个日期和状态为“ Ramped”的Person的SUM（小时）。否则，如果他们只有一个状态，则按日期和人返回SUM（小时）。我想要的结果是：

有什么建议吗？

Answer 1

用例语句有条件地求和。假设只有两种状态：倾斜和倾斜

select  Date, Person,
    status = min(Status),
    Hours   = case  when count(*) > 1
            then sum(case when Status = 'Ramped' then Hours else 0 end)
            else sum(Hours)
            end
from   yourtable
group by Date, Person

Answer 2

这是未经测试的，因为OP的数据是图像（我不打算重新输入），但是，一种方法是使用NOT EXISTS：

SELECT *
FROM YourTable YT
WHERE [Status] = 'Ramping'
   OR NOT EXISTS (SELECT 1
                  FROM YourTable e
                  WHERE e.[Date] = YT.[Date]
                    AND e.Person = YT.Person
                    AND e.[Status] = 'Ramping');

Answer 3

;WITH x(D,Pr,status,H) AS
(
    SELECT GetDate(), 'A','1',8
    UNION ALL
    SELECT GetDate(), 'A','2',8
    UNION ALL 
    SELECT GetDate()-1, 'A','1',8       
)
SELECT TOP 1 WITH TIES  
    D,Pr,status,H
FROM x
ORDER BY 
    ROW_NUMBER() OVER (PARTITION BY D,Pr ORDER BY Status)

Answer 4

由于“斜行<斜行”（按字母顺序排列），因此您可以按人员和日期对有序状态值进行编号，然后仅采用第一个，例如：

WITH numbering ([Date], Person, [Status], [Hours], Ranking) AS (
  SELECT [Date], Person, [Status], [Hours]
    , RANK() OVER (PARTITION BY [Date], Person ORDER BY [Status])
  FROM YourTable WHERE [Status] IN ('Ramped', 'Ramping')
)
SELECT [Date], Person, [Status], [Hours]
FROM numbering
WHERE Ranking = 1;

Answer 5

将原始表命名为table1。这是使用CTE的示例。

WITH cte AS (
  SELECT  [Date],[Person],[Status],sum([Hours]) as Hours, 
         row_number() OVER(PARTITION BY [Date],[Person] ORDER BY [Status]) AS rn
  FROM [LEGALDB2].[dbo].[table1]
  group by [Date],[Person],[Status]
  )
 select [Date],[Person],[Status],[Hours] 
 from cte
 where rn=1