Question

所以我有这个数组：

var utf = Array(
    a: Array('á','à','ã','Á','À','Ã'),
    e: Array('é','ê','É','È'),
    i: Array('í','Í'),
    o: Array('ó','õ','Ó','Õ'),
    u: Array('ú','Ú'),
    c: Array('ç','Ç')   
);

我想运行一个for循环，如：

for(i = 0; i < utf.length; i++){
    for (j = 0; j < utf[i].length; j++){
         mystring.replace(utf[i][j], <utf[i][arrayname]>);
    }
}

这可能吗？怎么样？你会以不同的方式做到这一点吗？如何？

非常感谢

Answer 1

function doReplace(mystring)
{
  var utf = {
      a: ['á','à','ã','Á','À','Ã'],
      e: ['é','ê','É','È'],
      i: ['í','Í'],
      o: ['ó','õ','Ó','Õ'],
      u: ['ú','Ú'],
      c: ['ç','Ç']
  };

  for(var c in utf)
  {
    var charArray = utf[c];
    for (var j = 0; j < charArray.length; j++)
    {
      mystring= mystring.replace(new RegExp(charArray[j], "g"), c);
    }
  }
  return mystring;
}

这很慢。如果您的浏览器编译正则表达式（如大多数新版本），最快的解决方案可能是每个字符使用一个正则表达式：

var utf = {
    a: ['á','à','ã','Á','À','Ã'],
    e: ['é','ê','É','È'],
    i: ['í','Í'],
    o: ['ó','õ','Ó','Õ'],
    u: ['ú','Ú'],
    c: ['ç','Ç']
};

var utfRegexes = {};

// Sadly javascript isn't C# so something that could be done in two lines
// of LINQ need to be unrolled.
for(var c in utf)
{
  console.log("in " + c);
  var chars = "[";
  for (var j = 0; j < utf[c].length; j++)
  {
    chars += utf[c][j];
  }
  chars += "]";
  utfRegexes[c] = new RegExp(chars, "g");
}

function doReplaceRegex(mystring)
{   
  for(var c in utfRegexes)
  {
      mystring = mystring.replace(utfRegexes[c], c);        
  }
  return mystring;
}

Answer 2

Javascript中的数组仅支持整数索引。使用对象。我还建议使用JSON作为创建新数组和对象的最可读和最简单的方法：

var utf = {
    a: ['á','à','ã','Á','À','Ã'],
    e: ['é','ê','É','È']
    //etc
};
for (var i in utf)
{
    //In the i variable, you'll find name of array of chars: a, e, i, o, u, c...
    //The array of chars can be found in utf[i]
}

Answer 3

可以使用关联数组（即对象）而不是普通数组。

var utf = {
    'a': ['á','à','ã','Á','À','Ã'],
    'e': ['é','ê','É','È'],
    'i': ['í','Í'],
    'o': ['ó','õ','Ó','Õ'],
    'u': ['ú','Ú'],
    'c': ['ç','Ç']
    }

    var mystring = 'abgvÁÓÚ';
    for(var i in utf){
        for(var j = 0; j < utf[i].length; j++){
        mystring.replace(utf[i][j], i);
        }
    }

Answer 4

// Just a semantic reformat, lacks speed improvements
var utf = Array(
  Array('a', 'á','à','ã','Á','À','Ã'),
  Array('e', 'é','ê','É','È'),
  Array('i', 'í','Í'),
  Array('o', 'ó','õ','Ó','Õ'),
  Array('u', 'ú','Ú'),
  Array('c', 'ç','Ç')  
);
for(i = 0; i < utf.length; i++){
    for j = 1; j < utf[i].length; j++){
         mystring.replace(utf[i][j], utf[i][0]);
    }
}

javascript获取数组名称

4 个答案: