Question

我有一个存储销售目标的表-这些目标通常是按月设置，但按天输入-这意味着每日目标是月份目标除以天数。

这是输入目标的劳动密集型方法，因此我想重新创建带有开始日期和结束日期的表：

WITH targets AS (
  SELECT DATE '2018-01-01' AS dateStart, DATE '2018-01-31' AS dateEnd, 'uk' AS market, NUMERIC '1550' AS quantity
  UNION ALL SELECT '2018-02-01', '2018-02-28', "uk", 560
)

在我的查询中，我需要生成一个日期数组（dateStart至dateEnd），然后针对该数组中的每个日期，应用市场并将目标除以该数组中的日期数-但我无法正常运作。我正在寻找类似的东西：

SELECT 
  *,
  (SELECT market FROM targets WHERE dr IN GENERATE_DATE_ARRAY(targets.dateStart, targets.dateEnd, INTERVAL 1 DAY)) AS market,
  (SELECT SAFE_DIVIDE(budget, COUNT(GENERATE_DATE_ARRAY(targets.dateStart, targets.dateEnd, INTERVAL 1 DAY)) FROM targets WHERE dr IN GENERATE_DATE_ARRAY(targets.dateStart, targets.dateEnd, INTERVAL 1 DAY)) AND targets.market = market AS budget
FROM UNNEST(GENERATE_DATE_ARRAY(targets.dateStart, targets.dateEnd, INTERVAL 1 DAY)) AS dr

这意味着更少的数据输入和更少的源表中的行（这是一个Google表格，因此最终将达到限制）。感谢您的帮助。

Answer 1

以下是用于BigQuery标准SQL

#standardSQL
WITH targets AS (
  SELECT DATE '2018-01-01' AS dateStart, DATE '2018-01-31' AS dateEnd, 'uk' AS market, NUMERIC '1550' AS quantity
  UNION ALL SELECT '2018-02-01', '2018-02-28', "uk", 560
)
SELECT market, day, quantity / days AS target
FROM targets, 
  UNNEST(GENERATE_DATE_ARRAY(dateStart, dateEnd)) day, 
  UNNEST([DATE_DIFF(dateEnd, dateStart, DAY) + 1]) days
ORDER BY market, day

使用BigQuery对日期数组执行子查询

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