我有一个自定义的wp_login_form():
<?php
if (!is_user_logged_in()) { // Display WordPress login form:
$args = array(
'redirect' => '/?page_id=502',
'form_id' => 'loginform2',
'label_log_in' => __('Login'),
'label_username' => __(''),
'label_password' => __(''),
'id_username' => 'account1',
'id_password' => 'password1',
'id_remember' => 'rememberme',
'id_submit' => 'login1',
'remember' => false,
);
if ($registered) {
$args['value_username'] = $user_login->user_login;
}
wp_login_form($args);
} else {
wp_loginout(home_url()); // Display "Log Out" link.
echo " | ";
wp_register('', ''); // Display "Site Admin" link.
}
?>
这是我的表格。
<form name="loginform2" id="loginform2" action="url/wp-login.php" method="post" class="bebas">
<p class="login-username">
<label for="account1"></label>
<input type="text" name="log" id="account1" class="input" value="" size="20" placeholder="E-MAIL">
</p>
<p class="login-password">
<label for="password1"></label>
<input type="password" name="pwd" id="password1" class="input" value="" size="20" placeholder="PASSWORT">
</p>
<p class="login-submit">
<input type="submit" name="wp-submit" id="login1" class="button button-primary" value="Login">
<input type="hidden" name="redirect_to" value="?page_id=502">
</p>
</form>
现在,我已经实现了AJAX
<script>
jQuery(document).ready(function(){
jQuery("#login1").click(function() {
jQuery('#message').hide().html('');
var input_data = jQuery('#loginform2').serialize();
var logUser = jQuery('#account1').val();
var logPass = jQuery('#password1').val();
if(logUser == '' && logPass != ''){ jQuery('#message').show().html('Your Username is empty!'); return false; }
if(logPass == '' && logUser != ''){ jQuery('#message').show().html('Your Password is empty!'); return false; }
if(logUser == '' && logPass == ''){ jQuery('#message').show().html('Your Username and Password is empty!'); return false; }
jQuery.ajax({
type: "POST",
url: "<?php echo site_url('wp-login.php','login_post'); ?>",
data: input_data,
success: function(msg) {
// login success. redirect users to some page.
jQuery(location).attr('href', '<?php echo home_url(); ?>');
},
error: function(msg) {
// login error.
jQuery('#message').show();
jQuery('#message').html("<?php _e('Your login is not correct. Please try again.'); ?>");
jQuery('#loading').hide();
}
});
return false;
});
});
</script>
我的问题是我收到一条错误消息,但是如果输入正确的地址,我无法登录。。 我认为问题出在网址中。但是我不知道我应该使用什么网址。我对ajax的经验非常基础,我需要帮助。