Question

我的数组：

Array
(
    [0] => Array
        (
            [id] => 1
            [name] => cat
            [tag] => animal
        )

    [1] => Array
        (
            [id] => 3
            [name] => cat women
            [tag] => human
        )

)

我的字符串

$string = 'cat is not cat women, my women at home';

如何查找和更改出现在$ string上与$ array匹配的单词？这样我就可以得到一个新的字符串：

动物不是人类，我的女人在家里

预先感谢

Answer 1

我的版本

$array = [['name' => 'cat', 'tag' => 'animal'], ['name' => 'cat women', 'tag' => 'human']];
$string = 'cat is not cat women, my women at home';

usort($array, function($a, $b) { // first sort by length of varchar
    return strlen($a['name']) < strlen($b['name']);
});

$string = str_replace( array_column($array, "name"), array_column($array, "tag"), $string);

echo $string;

输出：动物不是人类，我的女人在家里

Answer 2

请尝试以下逻辑：

$arrrrr = array
(
    "0" => array
        (
            "id" => 1,
            "name" => "cat",
            "tag" => "animal"
        ),

    "1" => array
        (
            "id" => 3,
            "name" => "cat women",
            "tag" => "human"
        )

);

$string = "cat is not cat women, my women at home";
foreach($arrrrr as $sarr){
  $pos = strpos($string, strtolower($sarr['name']));
    if($pos !==false){          
       $string =  substr_replace($string,$sarr['tag'],$pos,strlen($sarr['name']));

    }
}
echo $string;

输出：

animal is not human, my women at home

我认为这对您会有所帮助。

如何查找和更改出现在与数组匹配的字符串上的单词

2 个答案: