如何将参数传递给另一个类中的数组?

时间:2018-07-11 02:19:48

标签: java arrays oop object constructor

这是我第一次在StackOverflow上发帖,但是我已经访问了很多次。我正在上一门计算机科学课,但遇到了一个无法通过研究解决的问题。任务是创建一个带有实例变量和构造函数的NBATeam类,以及一个NBA客户端,该客户端从用户那里接收球员名称的参数并将它们传递给第一类的数组。

所以我遇到的问题是运行程序时,我输入播放器名称并将其传递给数组,第一个名称数组被删除。不过,输入到最新数组中的名称是可以的。

如果我的用语不正确,我深表歉意,我还是个新手!

非常感谢您能给我的帮助。

我将在下面插入我的代码。我的问题是它说[null]。另外,我为第一支球队输入了bob,为第二支球队输入了brian,但是bob在第二支队伍中。

请帮助!

Create NBA team of Heats
Add a player to team Heats? (yes/no)
yes
Enter the name of the player: 
bob
Add one more player to Heats?
no
Create NBA team of Spurs
Add a player to team Spurs? (yes/no)
yes
Enter the name of the player: 
brian
Add another player to Spurs?
no
***Heat Wins!***
Heats[null]Wins: 4 Loses: 0
Spurs[bob]Wins: 0 Loses: 4

import java.util.*;

public class NBA {
public static void main(String[] args) {
    Scanner input = new Scanner(System.in);
    String ifAddPlayer, playerName = null;


    //construct Team Heat
    System.out.println("Create NBA team of Heats");
    NBATeam heats = new NBATeam("Heats");
    System.out.println("Add a player to team Heats? (yes/no)");
    ifAddPlayer = input.next();

        while(ifAddPlayer.equalsIgnoreCase("yes")) {
            System.out.println("Enter the name of the player: ");

            heats.addPlayer(playerName);
            playerName = input.next();

            System.out.println("Add one more player to Heats?");
            ifAddPlayer = input.next();
        }

    //construct team Spurs.
    System.out.println("Create NBA team of Spurs");
    NBATeam spurs = new NBATeam("Spurs");
    System.out.println("Add a player to team Spurs? (yes/no)");
    ifAddPlayer = input.next();

        while(ifAddPlayer.equalsIgnoreCase("yes")) {
            System.out.println("Enter the name of the player: ");

            spurs.addPlayer(playerName);
            playerName = input.next();

            System.out.println("Add another player to Spurs?");
            ifAddPlayer = input.next(); 
        }

        playAGame(heats,spurs);
         System.out.println(heats.toString());
            System.out.println(spurs.toString());

}
public static void playAGame(NBATeam heats, NBATeam spurs) {

        for(int game = 0; game < 7; game++){

        double score = Math.random();

        if (score < .5) {
        heats.winAgame(spurs);

        }
        else{    
        spurs.winAgame(heats);

        }
        if(spurs.nWin()==4 || heats.nWin()==4) {
            break;
        }
        }
        if(spurs.nWin()>heats.nWin()) {
            System.out.println("***Spurs Win!***");
        }
        else
            System.out.println("***Heat Wins!***");
    }
}




import java.util.Arrays;

public class NBATeam {
private String sTeamName;
private int nWin;
private int nLoss;
private int nPlayer;

private String [] playerArray = new String[nPlayer];

public NBATeam(String sTeamName) {
    this.sTeamName = sTeamName;
    nPlayer=0;

}
public int nWin() {
    return nWin;
}
public int nLoss() {
    return nLoss;
}
public String getTeamName(){        
    //gets team's Name
    return sTeamName;
}

public String toString() {
     return sTeamName + Arrays.toString(playerArray)+ "Wins: " + nWin + 
            " Loses: " + nLoss;

}

public void lossAgame() {
    this.nLoss++;
}
public void winAgame(NBATeam team2) { //To win over the team
    nWin++;
    team2.setLoss(team2.nLoss()+1);
    //teamB.lossAgame();
}

public int getLossNumber() {
    return this.nLoss;
}
public void setLoss(int l) {
    this.nLoss=l;
}

public int getWinNumber() {
    return this.nWin;
}
public void setWin(int w) {
    this.nWin=w;
}
public void addPlayer(String player) {

    String temp[] = playerArray;
    playerArray = Arrays.copyOf(temp, temp.length+1);
    playerArray[nPlayer] = player;
    nPlayer++;

}

public String[] getPlayerArray() {
    return playerArray;
}

public void setPlayerArray(String[] playerArray) {
    this.playerArray = playerArray;
}
}

1 个答案:

答案 0 :(得分:1)

您从null中的初始值playerName开始,然后在获取值之前添加playerName。这个

heats.addPlayer(playerName);
playerName = input.next();

反了。应该是

playerName = input.next();
heats.addPlayer(playerName);

然后,您一致。这个

spurs.addPlayer(playerName);
playerName = input.next();

同样被颠倒。并且应该是

playerName = input.next();
spurs.addPlayer(playerName);

我会 建议 来限制变量的可见性。如果你有

String playerName = input.next();
heats.addPlayer(playerName);

这将限制在设置播放器之前添加播放器的可能性。