在Postgres的左加入

Question

确定此SQL查询出了什么问题

select j.* from judge as j 
left join user as u on j.user_id = u.id 
where u.email="john@example.com";
ERROR:  column "john@example.com" does not exist

Answer 1

您使用双引号，而实际上应该使用单引号。 单引号表示值，而双引号表示列和表等。 You can find out more about the difference here.