Question

通过以下Android代码，我连接到互联网上的html页面并提取几行。代码在大多数情况下执行良好，但有时会挂起。我必须按下手机上的后退按钮才能获得“强制关闭”对话框。它总是在模拟器上运行良好（在PC上有快速连接）。

那么，由于我手机上的EDGE / GPRS连接速度慢，代码是否会挂起？
我应该插入套接字超时吗？
代码挂起还有什么其他原因？
如何阻止代码挂起？有没有办法在重新尝试之前捕获错误并将消息返回给用户？

请帮忙。

   private String readFile(){
    List<String> scores = new ArrayList<String>();
    String result="";
    String score = "";
    HttpClient client = new DefaultHttpClient();
    HttpGet request = new HttpGet("http://www.espncricinfo.com/icc_cricket_worldcup2011/engine/current/match/433567.html");
    try{
        HttpResponse response = client.execute(request);
        //txtResult.setText(HttpHelper.request(response));

        try{
            InputStream in = response.getEntity().getContent();
            BufferedReader reader = new BufferedReader(new InputStreamReader(in));
            StringBuilder str = new StringBuilder();
            String line = null;
            while((line = reader.readLine()) != null){
                str.append(line + "\n");
            }
            in.close();

            result = str.toString();
            //result = str.toString().substring(1,500);

            Pattern p = Pattern.compile(
                    "<title>(.*)</title>",
                     Pattern.DOTALL
                );
            Matcher matcher = p.matcher(
                     result
                );

            if (matcher.find())
            {
                score = matcher.group(1).toString();
            }

             TextView tv = (TextView)findViewById(R.id.textview);
             tv.setText(score);

            return score;

        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
            Toast.makeText(this, "IOException e  = " + e.toString(), Toast.LENGTH_LONG).show();
            Log.d(TAG, "IOException e  = " + e.toString());

            return "IOException e  = " + e.toString();
         }catch(Exception ex){
            result = "Error";
            ex.printStackTrace();
            Toast.makeText(this, "Exception ex  = " + ex.toString(), Toast.LENGTH_LONG).show();
            Log.d(TAG,"Exception ex  = " + ex.toString());
            return "Exception ex  = " + ex.toString();
        }
    } catch (SocketTimeoutException e) {
        e.printStackTrace();
        Toast.makeText(this, "SocketTimeoutException e  = " + e.toString(), Toast.LENGTH_LONG).show();
        Log.d(TAG, "SocketTimeoutException e  = " + e.toString());
        return "SocketTimeoutException e  = " + e.toString();
    }catch(Exception ex){
        Toast.makeText(this, "Exception ex1  = " + ex.toString(), Toast.LENGTH_LONG).show();
          Log.d(TAG, "Exception ex1  = " + ex.toString());
          return  "Exception ex1  = " + ex.toString();
    }
}

Answer 1

您是否在应用程序的主线程中运行此操作？较长的运行进程应在单独的线程中执行，以避免减慢用户的主线程速度。

例如，请参阅Android Developer guide。

Android：应用程序在尝试读取HTML文件时挂起

1 个答案: