Question

说我有一个看起来像这样的json：

"data": [{
        "name": "United States Department of Homeland Security",
        "TotalCount": 0,
        "UniqueCount": 3,
        "AveragedEntry": {
            "text": "United States Department of Homeland Security",
            "relevance": 0.20341,
        },
        "WeightedEntry": {
            "text": "United States Department of Homeland Security",
            "relevance": "NaN",
        }
}]

我想要的是一个对象的json数组，如下所示：

"data": [{
            "name": "United States Department of Homeland Security",
            "TotalCount": 0,
            "UniqueCount": 3,
            "AveragedEntry": 0.20341,
            "WeightedEntry": "NaN"
    }]

在其中为父属性AveragedEntry和WeightedEntry分配了相关性属性的值。

关于如何循环/创建/操作json对象有很多问题，但是我还没有遇到要解决的特定问题。

使用javascript / jquery是否可能？

我尝试对我的初始json进行深层复制，并遍历该对象并顺利地推送嵌套的对象。任何帮助表示赞赏，谢谢。

Answer 1

var test = {
  "data": [{
    "name": "United States Department of Homeland Security",
    "TotalCount": 0,
    "UniqueCount": 3,
    "AveragedEntry": {
      "text": "United States Department of Homeland Security",
      "relevance": 0.20341,
    },
    "WeightedEntry": {
      "text": "United States Department of Homeland Security",
      "relevance": "NaN",
    }
  }]
};

//make a copy of the object
var newThing = JSON.parse(JSON.stringify(test));

newThing.data.forEach(function(element){
  //unnest the values that you want
  element.AveragedEntry = element.AveragedEntry.relevance;
  element.WeightedEntry = element.WeightedEntry.relevance;
});

//original is not changed
console.log(test);
//new element exists
console.log(newThing);

Answer 2

使用Array.map

let data = [{"name": "United States Department of Homeland Security","TotalCount": 0,"UniqueCount": 3,"AveragedEntry": {"text": "United States Department of Homeland Security","relevance": 0.20341,},"WeightedEntry": {"text": "United States Department of Homeland Security","relevance": "NaN",}}];

data = data.map(({AveragedEntry, WeightedEntry, ...rest}) => Object.assign(rest,{AveragedEntry : AveragedEntry.relevance, WeightedEntry : WeightedEntry.relevance}));
console.log(data);

Answer 3

您可以使用Array.map()将数组转换为所需的结构：

var data = [{
        "name": "United States Department of Homeland Security",
        "TotalCount": 0,
        "UniqueCount": 3,
        "AveragedEntry": {
            "text": "United States Department of Homeland Security",
            "relevance": 0.20341,
        },
        "WeightedEntry": {
            "text": "United States Department of Homeland Security",
            "relevance": "NaN",
        }
}];

var res = data.map((obj)=>{
   obj.AveragedEntry = obj.AveragedEntry.relevance;
   obj.WeightedEntry = obj.WeightedEntry.relevance;
   return obj;
});
console.log(res);

Answer 4

不指定AveragedEntry和WeightedEntry，

您可以使用map遍历数组。使用Object.entries将对象转换为数组，然后使用reduce制作新对象。

检查值是否为对象，如果是，则使用relevance属性。

let data = [{"name":"United States Department of Homeland Security","TotalCount":0,"UniqueCount":3,"AveragedEntry":{"text":"United States Department of Homeland Security","relevance":0.20341},"WeightedEntry":{"text":"United States Department of Homeland Security","relevance":"NaN"}}];

//Loop each array element using `.map()`
//variable o holds the array elements.
let result = data.map(o => {
  
  //Use `Object.entries()` to convert each array element (object) into an array
  //This will return a multi dimensional array with element 0 the key and element 1 the value
  //Variable `k` is the key of the object. Like: name, AveragedEntry, WeightedEntry
  //Variable `v` is the corresponding value of the key. Like 0 or  {"text": "United States Department of Homeland Security","relevance": 0.20341,}

  //If the `v` (value) is a type object, use the relevance and assign the value to the accumulator variable `c`
  return Object.entries(o).reduce((c, [k, v]) => {
    if (typeof v === 'object') c[k] = v.relevance;
    else c[k] = v;
    return c;
  }, {});
});

console.log(result);

更短版本：使用Object.assign向对象添加属性和值。

let data = [{"name":"United States Department of Homeland Security","TotalCount":0,"UniqueCount":3,"AveragedEntry":{"text":"United States Department of Homeland Security","relevance":0.20341},"WeightedEntry":{"text":"United States Department of Homeland Security","relevance":"NaN"}}]

let result = data.map(o => Object.entries(o).reduce((c, [k, v]) => Object.assign(c, typeof v === 'object' ? {[k]: v.relevance} : {[k]: v}), {}));

console.log(result);

Answer 5

您可以使用Array.map函数为此类数据转换创建管道。

let data = [{
        "name": "United States Department of Homeland Security",
        "TotalCount": 0,
        "UniqueCount": 3,
        "AveragedEntry": {
            "text": "United States Department of Homeland Security",
            "relevance": 0.20341,
        },
        "WeightedEntry": {
            "text": "United States Department of Homeland Security",
            "relevance": "NaN",
        }
}];

// Map the data into the new data structure.
var mapped = data.map(e => ({ 
    name: e.name, 
    totalCount: e.TotalCount, 
    uniqueCount: e.UniqueCount,
    averagedEntry: e.AveragedEntry.relevance,
    weightedEntry: e.WeightedEntry.relevance
}));

console.log(mapped)

与使用JavaScript元编程api的某些答案相比，这可能有点罗word，但是我认为简单性对于可读性是最好的。

如何将嵌套json属性的值分配给父对象？

5 个答案: