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Question

我有以下模型：

Class Party < ApplicationRecord
  belongs_to :partyable, polymorphic: true
end

Class Person < ApplicationRecord
  has_one :party, as: :partyable, dependent: :destroy
end

Class Organization < ApplicationRecord
  has_one :party, as: :partyable, dependent: : destroy
end

女巫看看这些桌子：

class CreatePeople < ActiveRecord::Migration[5.2]
  def change
    create_table :people do |t|
      t.string :first_name
      t.string :last_name, null: false
      t.string :gender
      t.text :notes
      t.timestamps
    end
  end
end

class CreateOrganizations < ActiveRecord::Migration[5.2]
  def change
    create_table :organizations do |t|
      t.string :name, null: false
      t.string :description
      t.text :notes
      t.timestamps
    end
  end
end

class CreateParties < ActiveRecord::Migration[5.2]
  def change
    create_table :parties do |t|
      t.references :partyable, polymorphic: true
      t.text :notes
      t.timestamps
    end
  end
end

现在，我想搜索“派对”模型并返回名称（如果该派对是组织）或姓（如果该人物是“人”）的给定字符串的派对数组。

目前，当我尝试向人们查询时，我没有成功：

Party.joins("INNER JOIN people ON people.id = parties.partyable_id").select('parties.*,people.last_name').where('last_name like ?', "%Smith%").first

我知道

ActiveRecord::StatementInvalid: SQLite3::SQLException: no such column: last_name: SELECT  parties.*,people.last_name FROM "parties" INNER JOIN people ON people.id = parties.partyable_id WHERE (last_name like '%Smith%') ORDER BY "parties"."id" ASC LIMIT ?

为什么找不到last_name列？我可以以某种方式改进模型以获得想要的东西吗？有人可以给我建议/提示/解决方案吗？

Answer 1

好！典型的输入错误。我键入了 las_name 而不是 last_name 。因此，一种有效的解决方案是：

在models / Party.rb

中

def self.search(search)
  r1 = joins("INNER JOIN people ON people.id = parties.partyable_id").where('last_name like ?', "%#{search}%")
  r2 = joins("INNER JOIN organizations ON organizations.id = parties.partyable_id).where('name like ?', "%#{search}%")
  r = r1 + r2
  r.uniq{|x| x.id}
end

编辑

我找到了更好的解决方案

scope :search, ->(s) {
    joins("LEFT JOIN people ON people.id = parties.partyable_id").
    joins("LEFT JOIN organizations ON organizations.id = parties.partyable_id").
    where(people.last_name LIKE :s OR organizations.name LIKE :s', s: "%#{s}%")
  }

有人可以提供更好的方法吗？

在红宝石中搜索多面模型

1 个答案:

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