Question

仅当提供其他参数时，我才需要应用条件开关参数。任何人都可以让我知道如何在C＃中实现这一目标吗？

我想通过以下方式在Powershell终端上访问命令。

修改

 Get-Parameter # this will process other path of the code and won't throw an error. (e.g. Not providing name of parameter, it would return all parameters in the container )

Get-Parameter -Name "Epics" -Writeable # writeable is switch parameter
Get-Parameter -Writeable # should throw an error ( Writeable switch only allows when Name parameter is provided.

以下是C＃Commandlet代码。

[Cmdlet(VerbsCommon.Get, "Parameter")]
public class GetParameter : PSCmdlet
{
    [Parameter(
        Position = 1,
        Mandatory = false,
        ValueFromPipeline = true,
        ValueFromPipelineByPropertyName = true, ParameterSetName = "Name")
    ]
    public string Name { get; set; }

    [Parameter(Mandatory = true, ParameterSetName = "Name" ,ValueFromPipeline = true,
    ValueFromPipelineByPropertyName = true)]
    public SwitchParameter Writeable { get; set; } = false;
}

Answer 1

根据评论，我认为您需要这样的内容：

[Cmdlet(VerbsCommon.Get, "Parameter")]
public class GetParameter : PSCmdlet
{
    [Parameter(
        Position = 0,
        Mandatory = true,
        ValueFromPipeline = true,
        ValueFromPipelineByPropertyName = true,
        ParameterSetName = "Name")
    ]
    public string Name { get; set; }

    [Parameter(
        Mandatory = false,
        ParameterSetName = "Name",
        ValueFromPipeline = true,
        Position = 1,
        ValueFromPipelineByPropertyName = true)]
    public SwitchParameter Writeable { get; set; } = false;
}

Powershell C＃Commandlet条件开关参数

1 个答案: