在我的React应用程序中,我试图单击复选框以捕获一些事件以进行一些状态过滤,并仅显示需要的项目。
event
来自孩子的复选框,里面有一些name
。有3个复选框,所以我需要知道单击name
的那个。
其中一些
<input
type="checkbox"
name="name1"
onClick={filterHandler}
/>Something</div>
状态类似于
state = {
items = [
{
name: "name1",
useful: true
},{
name: "name2",
useful: false
}],
filteredItems: []
}
这里是处理程序
filterHandler = (evt) => {
let checked = evt.target.checked;
let name = evt.target.name;
let filteredItems = this.state.items.filter(item => {
return item[name] === checked; // filtered [{...},{...}...]
});
// when filtered - push to state and show all from here in <ItemsList />
this.setState({ filteredItems })
}
用于“显示”的ItemsList组件是这样的:
<ItemsList
items={this.state.filteredItems.length === 0 ? this.state.items : this.state.filteredItems}
/>
当复选框为唯一复选框时-它可以正常工作。但是我有三个盒子-出现了并发症:
1)选中下一个框时,我使用未过滤的原始项目数组-为此,我需要已经过滤的数组。
2)我不能使用经过过滤的filteredItems
数组,因为当取消选中该数组时,该数组为空。拥有第三个“临时”数组似乎有点奇怪。
我尝试过这种方式,也很相似
this.setState({
filteredItems: this.state.items.filter(item => {
if (item[name] === checked) {
console.log('catch');
return Object.assign({}, item)
} else {
console.log('no hits')
}
})
这几乎是一件好事,但是当取消选中filteredItems
时,它们会填充相反的值((
我认为有更好的方法,请提出建议。
答案 0 :(得分:1)
您可以引入一个附加状态checked
,用于存储检查的值,并将其用于过滤。
示例(CodeSandbox)
class App extends React.Component {
state = {
items: [
{
name: "name1",
useful: true
},
{
name: "name2",
useful: false
}
],
checked: {}
};
filterHandler = event => {
const { name } = event.target;
this.setState(previousState => {
const checked = { ...previousState.checked };
checked[name] = !checked[name];
return { checked };
});
};
render() {
const { items, checked } = this.state;
let filteredItems = items.filter(item => checked[item.name]);
filteredItems = filteredItems.length === 0 ? items : filteredItems;
return (
<div>
<div>
<input
type="checkbox"
name="name1"
value={checked["name1"]}
onClick={this.filterHandler}
/>Name 1
<input
type="checkbox"
name="name2"
value={checked["name2"]}
onClick={this.filterHandler}
/>Name 2
</div>
<div>
{filteredItems.map(item => <div key={item.name}> {item.name} </div>)}
</div>
</div>
);
}
}
答案 1 :(得分:1)
尝试使用该名称,然后将切换后的名称添加到状态中。
constructor(props) {
super(props);
this.state = {
isGoing: true,
numberOfGuests: 2
};
this.handleInputChange = this.handleInputChange.bind(this);
}
handleInputChange(event) {
const target = event.target;
const value = target.type === 'checkbox' ? target.checked : target.value;
const name = target.name;
this.setState({
[name]: value
});
}
<input
name="isGoing"
type="checkbox"
checked={this.state.isGoing}
onChange={this.handleInputChange} />
答案 2 :(得分:1)
您可以通过存储过滤器的选中状态来做到这一点。
例如,您的状态可能类似于:
state = {
items: [
{
name: "name1",
useful: true
},
{
name: "name2",
useful: false
}
],
filters: { 'name1': false, 'name2': false}, // key value pair name:checked
filteredItems: []
};
然后,您的点击/更改处理程序将同时更新已过滤列表和实际过滤器状态(已检查的状态)。
这是一个例子:
(更新:根据评论中的请求进行了评论)
// Using syntax: someFunc = (params) => { ... }
// To avoid having to bind(this) in constructor
onChange = evt => {
// const is like var and let but doesn't change
// We need to capture anything dependent on
// evt.target in synchronous code, and
// and setState below is asynchronous
const name = evt.target.name;
const checked = evt.target.checked;
// Passing function instead of object to setState
// This is the recommended way if
// new state depends on existing state
this.setState(prevState => {
// We create a new object for filters
const filters = {
// We add all existing filters
// This adds them with their existing values
...prevState.filters,
// This is like:
// filters[name] = checked
// which just overrides the value of
// the prop that has the name of checkbox
[name]: checked
};
// Object.keys() will return ["name1", "name2"]
// But make sure that "filters" in
// our initial state has all values
const activeFilterNames = Object.keys(filters).filter(
// We then filter this list to only the ones that
// have their value set to true
// (meaning: checked)
// We set this in the `const filter =` part above
filterName => filters[filterName]
);
// We get the full list of items
// (Make sure it's set in initial state)
// Then we filter it to match only checked
const filteredItems = prevState.items.filter(item =>
// For each item, we loop over
// all checked filters
// some() means: return true if any of the
// array elements in `activeFilterNames`
// matches the condition
activeFilterNames.some(
// The condition is simply the filter name is
// the same as the item name
activeFilterName => activeFilterName === item.name
)
);
// The object returned from setState function
// is what we want to change in the state
return {
// this is the same as
// { filter: filters,
// filteredItems: filteredItems }
// Just taking advantage of how const names
// are the same as prop names
filters,
filteredItems
};
});
};
我在这里使用JS / Babel的最新功能,但希望代码清晰。输入evt.target
setState()
这是一个完整的示例:
import * as React from "react";
import ReactDOM from "react-dom";
import "./styles.css";
class App extends React.Component {
state = {
items: [
{
name: "name1",
useful: true
},
{
name: "name2",
useful: false
}
],
filters: { name1: false, name2: false },
filteredItems: []
};
// Using syntax: someFunc = (params) => { ... }
// To avoid having to bind(this) in constructor
onChange = evt => {
// const is like var and let but doesn't change
// We need to capture anything dependent on
// evt.target in synchronous code, and
// and setState below is asynchronous
const name = evt.target.name;
const checked = evt.target.checked;
// Passing function instead of object to setState
// This is the recommended way if
// new state depends on existing state
this.setState(prevState => {
// We create a new object for filters
const filters = {
// We add all existing filters
// This adds them with their existing values
...prevState.filters,
// This is like:
// filters[name] = checked
// which just overrides the value of
// the prop that has the name of checkbox
[name]: checked
};
// Object.keys() will return ["name1", "name2"]
// But make sure that "filters" in
// our initial state has all values
const activeFilterNames = Object.keys(filters).filter(
// We then filter this list to only the ones that
// have their value set to true
// (meaning: checked)
// We set this in the `const filter =` part above
filterName => filters[filterName]
);
// We get the full list of items
// (Make sure it's set in initial state)
// Then we filter it to match only checked
const filteredItems = prevState.items.filter(item =>
// For each item, we loop over
// all checked filters
// some() means: return true if any of the
// array elements in `activeFilterNames`
// matches the condition
activeFilterNames.some(
// The condition is simply the filter name is
// the same as the item name
activeFilterName => activeFilterName === item.name
)
);
// The object returned from setState function
// is what we want to change in the state
return {
// this is the same as
// { filter: filters,
// filteredItems: filteredItems }
// Just taking advantage of how const names
// are the same as prop names
filters,
filteredItems
};
});
};
renderCheckboxes() {
return Object.keys(this.state.filters).map((name, index) => {
return (
<label key={index}>
<input
onChange={this.onChange}
type="checkbox"
checked={this.state.filters[name]}
name={name}
/>
{name}
</label>
);
});
}
render() {
const items = this.state.filteredItems.length
? this.state.filteredItems
: this.state.items;
return (
<div>
<div>{this.renderCheckboxes()}</div>
<ul>
{items.map(item => (
<li key={item.name}>
{item.name}
{item.useful && " (useful)"}
</li>
))}
</ul>
</div>
);
}
}
const rootElement = document.getElementById("root");
ReactDOM.render(<App />, rootElement);
您可以从这里尝试运行它:
https://codesandbox.io/embed/6z8754nq1n
您当然可以根据需要创建不同的变体。例如,您可能选择将过滤器移至呈现函数而不是更改事件,或者选择存储所选过滤器的方式等,或者直接使用它。最适合您的是:)